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JEE Mains Chemistry · Structure of Atom

Bohr Model: Radius, Energy and Velocity

In a one-electron atom or ion, Bohr's orbits have fixed radii, energies and speeds, and each scales with the orbit number n and the nuclear charge Z.

Why this matters

Twenty-five PYQs, nineteen of them multiple choice, and five from 2026 — the largest page in the chapter. Seven scale an orbit radius with n²/Z; thirteen use the orbit energy, its kinetic and potential parts, the speed or the ionisation energy; five test what the Thomson, Rutherford and Bohr models could and could not explain. Three ideas cover the page.

Concept 1 of 3: Orbit radius and its scaling

Bohr fixed the electron's angular momentum at whole multiples of h/2πh/2\pi. That allows only certain orbits. Their radius grows as n2n^2, because outer orbits are much farther out. It shrinks as ZZ grows, because a larger nuclear charge pulls the electron in. Only one-electron species obey it: H, He+\mathrm{He^+}, Li2+\mathrm{Li^{2+}}, Be3+\mathrm{Be^{3+}}.

Definition

  • mvr=nh2πmvr=\dfrac{nh}{2\pi}, n=1,2,3,…n=1,2,3,\ldots
  • rn=a0n2Zr_n=a_0\dfrac{n^2}{Z}, with a0=52.9 pm=0.529 A˚a_0=52.9\ \mathrm{pm}=0.529\ \mathrm{\mathring{A}}.
  • Ratio of two orbits: r1r2=n12/Z1n22/Z2\dfrac{r_1}{r_2}=\dfrac{n_1^2/Z_1}{n_2^2/Z_2}.
  • Ground state is n=1n=1; the first excited state is n=2n=2.

Bohr radius

rn=52.9 n2Z pmr_n=52.9\,\frac{n^2}{Z}\ \mathrm{pm}

Worked example

An orbit of He+\mathrm{He^+} has radius 238.05 pm. Which orbit is it?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2026 · 6 Apr 2026 Shift 2 · Q27Moderate

Example 1 · Structure of Atom · Bohr Model: Radius, Energy and Velocity

The Bohr radius of a hydrogen like species is 70.53 pm . The species and the stationary state(n) are respectively (Given: Hydrogen atom Bohr radius is 52.9 pm )

The radius goes as n², not n

The sixth orbit of H is 3616=2.25\dfrac{36}{16}=2.25 times the fourth, not 64\dfrac{6}{4} times. Square the orbit numbers before you divide.

First excited state is n = 2

"First excited" is one step above the ground state, so n=2n=2. Using n=1n=1 or n=3n=3 is the common slip.

Concept 2 of 3: Orbit energy, kinetic and potential energy, and speed

A bound electron has negative total energy. Zero is the free electron at rest far away. The energy grows with Z2Z^2 and falls with n2n^2, so inner orbits of heavier ions are much deeper. Kinetic energy is the size of the total energy, and potential energy is twice the total. The speed grows with ZZ and falls with nn.

Definition

  • En=−2.18×10−18Z2n2 J=−13.6Z2n2 eVE_n=-2.18\times10^{-18}\dfrac{Z^2}{n^2}\ \mathrm{J}=-13.6\dfrac{Z^2}{n^2}\ \mathrm{eV}.
  • KE=−EnKE=-E_n, PE=2EnPE=2E_n.
  • Ionisation energy from the ground state: 13.6Z2 eV13.6Z^2\ \mathrm{eV}.
  • Energy to move between levels: ΔE=13.6Z2(1n12−1n22) eV\Delta E=13.6Z^2\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\ \mathrm{eV}.
  • vn=2.18×106Zn m s−1v_n=2.18\times10^{6}\dfrac{Z}{n}\ \mathrm{m\,s^{-1}}.
  • Other scalings: frequency of revolution ∝Z2/n3\propto Z^2/n^3; Coulomb force ∝Z3/n4\propto Z^3/n^4.

Bohr energy

En=−13.6 Z2n2 eVE_n=-13.6\,\frac{Z^2}{n^2}\ \mathrm{eV}

Worked example

Find the energy needed to excite the electron of He+\mathrm{He^+} from n=1n=1 to n=3n=3, in J and in eV.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2026 · 23 Jan 2026 Shift 1 · Q26Moderate

Example 2 · Structure of Atom · Bohr Model: Radius, Energy and Velocity

Which of the following statements regarding the energy of the stationary state is true in the following one-electron system ?

Every orbit energy is negative

A bound electron always has En<0E_n<0. An option with a plus sign on an orbit energy is wrong before you do any arithmetic. Kinetic energy is the only positive one.

KE is minus E, PE is twice E

KE=−EnKE=-E_n and PE=2EnPE=2E_n. So for E=−3.4 eVE=-3.4\ \mathrm{eV}, KE=+3.4 eVKE=+3.4\ \mathrm{eV} and PE=−6.8 eVPE=-6.8\ \mathrm{eV}.

Concept 3 of 3: Thomson, Rutherford, Bohr and the quantum model

Each model fixed what the last one could not explain. Thomson spread the positive charge out. Rutherford's scattering put it in a tiny nucleus. Bohr's fixed orbits explained hydrogen's lines. The quantum model kept Bohr's stationary states and photons, but dropped the definite circular path.

Definition

  • Thomson: positive charge spread evenly, electrons embedded in it. It predicts only small deflections of α\alpha-particles.
  • Rutherford: a tiny, dense, positive nucleus. It explains large-angle scattering. It cannot explain why the atom is stable or why its spectrum has lines.
  • Bohr: fixed orbits with mvr=nh/2πmvr=nh/2\pi. It works only for one-electron species. It fails for the Zeeman (magnetic) and Stark (electric) splitting of lines, and a definite orbit breaks the uncertainty principle.
  • Quantum model: the electron is a wave, described by an orbital (a probability region). It keeps stationary states and ΔE=hν\Delta E=h\nu.
ModelPicture of the atomWhat it explainedWhere it failed
ThomsonUniform sphere of positive charge with electrons embeddedThe atom is neutral overallPredicts only small deflections, so cannot explain large-angle scatteringQ
If Thomson were right, α-particles would pass through gold foil with only small deflections.
RutherfordTiny dense positive nucleus with electrons around itLarge-angle scattering; a few α-particles bounce backAn orbiting electron should radiate and spiral in; no line spectrum
BohrElectrons in fixed circular orbits, mvr = nh/2πStability and line spectrum of H, He⁺, Li²⁺Many-electron atoms (even Li⁺), Zeeman and Stark splitting; a definite path breaks the uncertainty principleQ
Li⁺ has two electrons, so Bohr's theory does not apply to it. Li²⁺ has one.
Quantum mechanicalElectron as a wave; orbitals are regions of probability ψ²All atoms, including many-electron onesKeeps stationary states and ΔE = hν, but drops the definite orbit
The one Bohr postulate the quantum model rejects: the electron moves in a definite circular orbit.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2025 · 3 Apr 2025 · Q26Moderate

Example 3 · Structure of Atom · Bohr Model: Radius, Energy and Velocity

Which of the following postulate of Bohr's model of hydrogen atom is not in agreement with quantum mechanical model of an atom?

Li⁺ is not a one-electron ion

Count the electrons: Li+\mathrm{Li^{+}} has two. Only H\mathrm{H}, He+\mathrm{He^+}, Li2+\mathrm{Li^{2+}}, Be3+\mathrm{Be^{3+}} and so on are hydrogen-like.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

Reference tables (1)

Thomson, Rutherford, Bohr and the quantum model4 rows
ModelPicture of the atomWhat it explainedWhere it failed
ThomsonUniform sphere of positive charge with electrons embeddedThe atom is neutral overallPredicts only small deflections, so cannot explain large-angle scatteringQ
If Thomson were right, α-particles would pass through gold foil with only small deflections.
RutherfordTiny dense positive nucleus with electrons around itLarge-angle scattering; a few α-particles bounce backAn orbiting electron should radiate and spiral in; no line spectrum
BohrElectrons in fixed circular orbits, mvr = nh/2πStability and line spectrum of H, He⁺, Li²⁺Many-electron atoms (even Li⁺), Zeeman and Stark splitting; a definite path breaks the uncertainty principleQ
Li⁺ has two electrons, so Bohr's theory does not apply to it. Li²⁺ has one.
Quantum mechanicalElectron as a wave; orbitals are regions of probability ψ²All atoms, including many-electron onesKeeps stationary states and ΔE = hν, but drops the definite orbit
The one Bohr postulate the quantum model rejects: the electron moves in a definite circular orbit.

Watch out for (5)

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