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JEE Mains Physics · Ray Optics

Optical Instruments and the Eye

A compound microscope magnifies by (L/fₒ)(D/fₑ) in normal adjustment, a telescope by fₒ/fₑ with its lenses fₒ + fₑ apart, and resolving power grows with the aperture and falls with the wavelength.

Why this matters

Twelve PYQs, ten of them multiple choice, and four from 2026. Seven are about magnifiers, microscopes and telescopes: the magnification in normal adjustment, the length of a telescope, a beam expander and the job of a reflecting telescope's second mirror. Five are about seeing detail: resolving power, a camera's focal length, and the defects of the eye and the lenses that correct them.

Concept 1 of 2: Magnification of microscopes and telescopes

Both instruments use two converging lenses, for opposite jobs. A microscope's objective has a short focal length and makes a large real image of a near object; the eyepiece then works as a magnifying glass on that image. A telescope's objective has a long focal length and makes a small real image of a distant object at its focus; the eyepiece magnifies the angle. In normal adjustment the final image is at infinity, so the eye is relaxed.

Definition

  • Simple microscope: the gain comes from bringing the object closer than D = 25 cm; at the eye, the image subtends the same angle as the object. M=D/fM = D/f with the image at infinity, 1+D/f1 + D/f with the image at D.
  • Compound microscope, normal adjustment: M=Lfo×DfeM = \dfrac{L}{f_o} \times \dfrac{D}{f_e}, with L the tube length.
  • Refracting telescope, normal adjustment: M=fofeM = \dfrac{f_o}{f_e}, length fo+fef_o + f_e. A wider objective gathers more light and resolves finer detail; it does not change M.
  • Beam expander: two converging lenses with a common focus, f1+f2f_1 + f_2 apart; output width over input width is f2/f1f_2/f_1.
  • Reflecting telescope: a concave mirror is the objective; a small secondary mirror sends the light out of the tube to the eyepiece.
InstrumentFirst elementMagnification, final image at infinityDistance between the elements
Simple microscopeOne short-focus convex lensD/fD/fOnly one lens
Compound microscopeShort-focus objective lensLfo⋅Dfe\dfrac{L}{f_o}\cdot\dfrac{D}{f_e}Set by the tube length L
Refracting telescopeLong-focus objective lensfo/fef_o/f_efo+fef_o + f_e
Reflecting telescopeConcave mirror, fo=R/2f_o = R/2fo/fef_o/f_eA secondary mirror folds the light to an eyepiece outside the tube
Beam expanderConvex lens of focal length f1f_1Beam width multiplied by f2/f1f_2/f_1f1+f2f_1 + f_2
D = 25 cm, the least distance of distinct vision. Normal adjustment puts the final image at infinity.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2026 · 21 Jan 2026 Shift 1 · Q25Moderate

Example 1 · Ray Optics · Optical Instruments and the Eye

In a microscope the objective is having focal length f0=2 cmf_{0} = 2\text{ }cm and eye-piece is having focal length fe=4 cmf_{e} = 4\text{ }cm. The tube length is 32 cm. The magnification produced by this microscope for normal adjustment is ____\_\_\_\_ .

A telescope's M is fₒ/fₑ, not fₑ/fₒ

The objective has the long focal length. Inverting the ratio gives a magnification below 1, which is never an option for a working telescope.

A wider objective does not raise the magnification

A larger aperture lets in more light and resolves more detail, but in normal adjustment M depends only on the focal lengths.

Normal adjustment uses D/fₑ, not 1 + D/fₑ

The extra 1 appears only when the final image is at the near point. Read where the final image is before choosing the formula.

Concept 2 of 2: Resolving power and defects of vision

A lens of finite size cannot make a point image: diffraction blurs it. Two points can be told apart only if their blurs do not overlap too much. A wider aperture and a shorter wavelength make the blur smaller. The eye has its own limits: the range from its near point to its far point, which spectacles correct.

Definition

  • Telescope: smallest resolvable angle θ=1.22λD\theta = \dfrac{1.22\lambda}{D}; resolving power D1.22λ\dfrac{D}{1.22\lambda}, with D the aperture.
  • Microscope: resolving power 2μsin⁡θ1.22λ\dfrac{2\mu\sin\theta}{1.22\lambda}. A liquid of larger μ between the object and the objective improves it.
  • Camera photographing a distant scene: image size over object size equals f over the distance, so f=distance×film sizescene sizef = \text{distance} \times \dfrac{\text{film size}}{\text{scene size}}.
  • Myopia: the far point is too close; a concave lens of focal length equal to minus the far-point distance corrects it.
  • Hypermetropia: the near point is too far; a convex lens forms, at the person's near point, a virtual image of an object at 25 cm.
  • Astigmatism: the cornea curves differently in different planes, so lines in one direction blur or look distorted; a cylindrical lens corrects it.
DefectWhat goes wrongCorrecting lensHow to find the lens
Myopia (short sight)Far point closer than infinityConcavef=−(far-point distance)f = -(\text{far-point distance})
Hypermetropia (long sight)Near point farther than 25 cmConvexIt images an object at 25 cm onto the near point
PresbyopiaThe near point recedes with age as focusing weakensConvex for reading, often in a bifocalAs for hypermetropia
AstigmatismUnequal curvature of the cornea; lines in one direction blurCylindricalShaped to correct the faulty plane only
A reading glass is tested at the near point: an object at 25 cm must appear at the person's own near point.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 30 January 2023 · Q4Moderate

Example 2 · Ray Optics · Optical Instruments and the Eye

A person has been using spectacles of power -1.0 dioptre for distant vision and a separate reading glass of power 2.0 dioptres. What is the least distance of distinct vision for this person:

Resolving power is not magnification

A stronger eyepiece enlarges the blur too. Only a wider aperture, a shorter wavelength or, in a microscope, a denser medium in front of the objective resolves finer detail.

A reading glass forms a virtual image

It images an object at 25 cm onto the person's near point, on the same side as the object. So v is negative and farther from the lens than 25 cm.

Blurred is not the same as distorted

Distant objects that look blurred point to myopia. Lines that look uneven or distorted point to astigmatism, which needs a cylindrical lens.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Reference tables (2)

Magnification of microscopes and telescopes5 rows
InstrumentFirst elementMagnification, final image at infinityDistance between the elements
Simple microscopeOne short-focus convex lensD/fD/fOnly one lens
Compound microscopeShort-focus objective lensLfo⋅Dfe\dfrac{L}{f_o}\cdot\dfrac{D}{f_e}Set by the tube length L
Refracting telescopeLong-focus objective lensfo/fef_o/f_efo+fef_o + f_e
Reflecting telescopeConcave mirror, fo=R/2f_o = R/2fo/fef_o/f_eA secondary mirror folds the light to an eyepiece outside the tube
Beam expanderConvex lens of focal length f1f_1Beam width multiplied by f2/f1f_2/f_1f1+f2f_1 + f_2
D = 25 cm, the least distance of distinct vision. Normal adjustment puts the final image at infinity.
Resolving power and defects of vision4 rows
DefectWhat goes wrongCorrecting lensHow to find the lens
Myopia (short sight)Far point closer than infinityConcavef=−(far-point distance)f = -(\text{far-point distance})
Hypermetropia (long sight)Near point farther than 25 cmConvexIt images an object at 25 cm onto the near point
PresbyopiaThe near point recedes with age as focusing weakensConvex for reading, often in a bifocalAs for hypermetropia
AstigmatismUnequal curvature of the cornea; lines in one direction blurCylindricalShaped to correct the faulty plane only
A reading glass is tested at the near point: an object at 25 cm must appear at the person's own near point.

Watch out for (6)

Test yourself on Ray Optics

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.