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JEE Mains Physics · Teaching notes

Thermodynamics — JEE Mains Physics

Thermodynamics has 125 past-year questions from 2021 to 2026, and 21 of them ask for a number rather than an option. One law carries the chapter: the heat given to a gas goes into its internal energy and into the work it does, Q = ΔU + W, with work done by the gas counted positive. Which process the gas follows decides how that heat splits, and adiabatic processes alone take nearly a quarter of the questions. Twenty-eight questions come with a figure, most of them a graph of a process, where work is an area and its sign comes from the direction. Marks are lost on Cp used for ΔU, on °C used in an efficiency, and on a semi-axis read off the wrong scale.

Every subtopic, worked example, formula and trap in one printable document — answers shown, ready to share.

Subtopic notes

Formula & revision sheet

14 formulas · 2 reference tables · 33 gotchas across all subtopics — the exam-eve cheat-sheet

First Law and Energy Bookkeeping

Formulas (2)

Watch out for (4)

Internal Energy and Heat Capacities

Formulas (3)

Watch out for (7)

Thermodynamic Processes and Work from P–V Graphs

Formulas (2)

Reference tables (1)

The standard processes and their W, Q and ΔU6 rows
ProcessHeld fixedWork by the gas WHeat into the gas QChange ΔU
IsothermalTemperaturenRTln⁡V2V1nRT\ln\dfrac{V_2}{V_1}Q = W0
Heat flows in, yet the temperature does not rise: all of it leaves as work.
IsochoricVolume0nCVΔTnC_V\Delta T, so Q = ΔUnCVΔTnC_V\Delta T
IsobaricPressurePΔV=nRΔTP\Delta V = nR\Delta TnCPΔTnC_P\Delta TnCVΔTnC_V\Delta T
AdiabaticNo heat exchangednR(T1−T2)γ−1\dfrac{nR(T_1 - T_2)}{\gamma - 1}0−W
CyclicStart and end state the sameArea enclosed on the P–V diagramQ = W0
Free expansion into a vacuumInsulated, no outside pressure000, so an ideal gas keeps its temperature
Physics sign convention: W is work done BY the gas and Q is heat INTO the gas, so Q = ΔU + W in every row.

Watch out for (6)

Adiabatic Processes

Formulas (2)

Reference tables (1)

True and false statements about adiabatic processes7 rows
Claim about an adiabatic processTrue or falseWhy
No heat crosses the boundaryTrueThat is the definition: Q = 0
The internal energy stays constantFalseΔU = −W, which is not zero unless no work is done
Q = 0 does not stop U changing: the work comes out of U.
An adiabatic compression raises the temperatureTrueThe work done on the gas goes into U, and U rises with T
Its P–V curve is steeper than the isotherm through the same pointTrueIts slope is γ times the isothermal slope
The molar heat capacity is zeroTrueC = Q/(nΔT) with Q = 0 while ΔT is not zero
The product TV stays constantFalseIt is TV^(γ−1) that stays constant
A free expansion into a vacuum follows PV^γ = constantFalseIt is irreversible; an ideal gas keeps its temperature
Every row follows from Q = 0 and Q = ΔU + W.
Cyclic Processes

Formulas (2)

Watch out for (4)

Heat Engines, Carnot Cycle and Refrigerators

Formulas (3)

Watch out for (6)

PYQ weightage by concept

16 concepts · 125 PYQs — where the marks actually sit, so you know what to drill first

First Law and Energy Bookkeeping15 PYQs · 12%
ConceptPYQsShare
Energy balances: phase changes, rates and pistons97%
The first law and its sign convention65%
Internal Energy and Heat Capacities20 PYQs · 16%
ConceptPYQsShare
How heat splits at constant pressure108%
Internal energy from Cv and the degrees of freedom65%
Molar heat capacity of any process43%
Thermodynamic Processes and Work from P–V Graphs25 PYQs · 20%
ConceptPYQsShare
The standard processes and their W, Q and ΔU119%
Work as the area under a P–V path108%
Processes given by an equation such as PV^x = constant43%
Adiabatic Processes30 PYQs · 24%
ConceptPYQsShare
The adiabatic relations PV^γ, TV^(γ−1) and P^(1−γ)T^γ1411%
Work done in an adiabatic process108%
True and false statements about adiabatic processes65%
Cyclic Processes12 PYQs · 10%
ConceptPYQsShare
Net work of a cycle as the enclosed area65%
A cycle worked leg by leg65%
Heat Engines, Carnot Cycle and Refrigerators23 PYQs · 18%
ConceptPYQsShare
Carnot efficiency η = 1 − T₂/T₁108%
Heat, work and temperature in engines and refrigerators86%
Engines in series and entropy54%

Test yourself on Thermodynamics

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.

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