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MHT-CET Chemistry · Transition and Inner Transition Elements

Lanthanoids and Actinoids: Membership, 4f Configurations and the Lanthanoid Contraction

The inner transition elements fill the 4f subshell (lanthanoids, La to Lu) or the 5f subshell (actinoids, Ac to Lr); their stable state is +3, the empty, half-filled and filled 4f subshells explain the extra +2 and +4 states, and the steady shrinking of the Ln³⁺ ion from La to Lu — the lanthanoid contraction — makes the hydroxides less basic along the series.

Why this matters

26 PYQs, 2 HARD. Seven ask which element is a lanthanoid, an actinoid or a rare earth, the last lanthanoid, or the one used in fibre amplifiers; seven are 4f configurations — Ce⁴⁺ f⁰, Tb⁴⁺ f⁷, Lu³⁺ with no unpaired electrons, the filled 4f of Yb and Lu, the half-filled 4f of Gd, and La³⁺ with no moment; seven are the lanthanoid contraction — the largest and smallest Ln³⁺, the weakest base, and the two HARD ionisation enthalpies (Yb); five are compounds and properties — Ln(OH)₃ twice, LnC₂, and two 'NOT true' statements. Four cards.

Concept 1 of 4

Which Element Is a Lanthanoid, Which an Actinoid

Intuition

Lanthanoids are the fifteen elements from lanthanum (57) to lutetium (71), in period 6; they and the actinoids are the rare earths. Actinoids run from actinium (89) to lawrencium (103), in period 7, and all are radioactive. A question gives four symbols and asks for one kind, so the fastest route is to know the two rows as lists and check which symbol sits in which.

Definition

  • Lanthanoids (4f, Z 57–71): La, Ce, Pr, Nd, Pm, Sm, Eu, Gd, Tb, Dy, Ho, Er, Tm, Yb, Lu (the last). Also called rare earth elements.
  • Actinoids (5f, Z 89–103): Ac, Th, Pa, U, Np, Pu, Am, Cm, Bk, Cf, Es, Fm, Md, No, Lr.
  • Lookalikes that are NOT f-block: Mo, Co, Hg, Zn, W, Cd (d-block).
  • Erbium is doped into optical fibres to make fibre amplifiers (erbium-doped fibre amplifiers).
SeriesZMembers to recognise
Lanthanoids (4f)57–71La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu
Actinoids (5f)89–103Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr
All actinoids are radioactive.
Tm, Pm, Sm are lanthanoids; Cm, Am, Np are actinoids — the look-alike pairs the options use.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 1Transition and Inner Transition ElementsEASY
Which from following elements belongs to the actinoids?

[Q56 · 9th May Shift 1 · 2023]

Matching by the ending of the name

Promethium, thulium and samarium are lanthanoids; americium, curium and neptunium are actinoids. The names do not sort them — the lists do.

Concept 2 of 4

4f Configurations and the +2 and +4 States

Intuition

The stable state is +3. An extra state appears where it reaches an empty (f⁰), half-filled (f⁷) or filled (f¹⁴) 4f subshell. Cerium is 4f¹ 5d¹ 6s²; losing four electrons gives Ce⁴⁺ with f⁰. Terbium is 4f⁹ 6s²; losing four gives Tb⁴⁺ with f⁷. Europium (f⁷) and ytterbium (f¹⁴) show +2 for the same reason. For Ln³⁺, count f electrons as Z − 57: La³⁺ f⁰ and Lu³⁺ f¹⁴ have no unpaired electrons and no magnetic moment, Gd³⁺ f⁷ has seven.

Definition

  • +4 state: Ce4+\text{Ce}^{4+} f⁰; Tb4+\text{Tb}^{4+} f⁷. +2 state: Eu2+\text{Eu}^{2+} f⁷, Yb2+\text{Yb}^{2+} f¹⁴.
  • Filled 4f: Yb [Xe]4f¹⁴ 6s² (expected ground state); Lu [Xe]4f¹⁴ 5d¹ 6s² (expected AND observed).
  • Half-filled 4f: Gd [Xe]4f⁷ 5d¹ 6s² (observed); Eu 4f⁷ 6s².
  • Ln3+\text{Ln}^{3+} f electrons = Z − 57. La3+\text{La}^{3+} f⁰ and Lu3+\text{Lu}^{3+} f¹⁴ → 0 unpaired, no magnetic moment.

f electrons in Ln³⁺

nf(Ln3+)=Z−57;unpaired={nfnf≤714−nfnf>7n_f(\text{Ln}^{3+}) = Z - 57;\quad \text{unpaired} = \begin{cases} n_f & n_f \le 7 \\ 14 - n_f & n_f > 7 \end{cases}

Worked example

How many unpaired electrons does Dy³⁺ have (Z = 66)?
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 2Transition and Inner Transition ElementsMODERATE
Which lanthanoid from following may exhibit +4 oxidation state with f0f^{0} configuration?

[Q73 · 26 April Shift I · 2025]

Expecting f⁷ at +3 for europium

Eu is already 4f⁷ as an atom, so Eu³⁺ is f⁶; it is Eu²⁺ that keeps the half-filled shell. The f⁷ ion at +3 is Gd³⁺, and the f⁷ ion at +4 is Tb⁴⁺.

Concept 3 of 4

The Lanthanoid Contraction: Size, Basicity and Ionisation Enthalpy

Intuition

Across the lanthanoids each step adds a proton and a 4f electron, and 4f electrons shield each other poorly. The effective nuclear charge rises, so the Ln³⁺ ion shrinks steadily from La³⁺ (largest) to Lu³⁺ (smallest). A smaller cation holds OH⁻ more tightly and gives it up less, so the hydroxides grow LESS basic: La(OH)₃ is the strongest base and Lu(OH)₃ the weakest. First ionisation enthalpies are low and close together, but a filled 4f¹⁴ subshell stands out: ytterbium has the highest of the options it appears with.

Definition

  • Ionic radius of Ln3+\text{Ln}^{3+} decreases La → Lu: largest La³⁺, smallest Lu³⁺.
  • Basicity of Ln(OH)3\text{Ln(OH)}_3 decreases La → Lu: weakest base Lu(OH)3\text{Lu(OH)}_3.
  • First ionisation enthalpy (kJ mol⁻¹): Nd 533, Ce 534, La 538, Dy 573, Gd 593, Tm 597, Yb 603 — Yb (4f¹⁴ 6s²) is highest of these.
  • Consequence: 4d and 5d elements of the same group are almost the same size (Zr and Hf).

Trends along the lanthanoids

r(La3+)>…>r(Lu3+);La(OH)3>…>Lu(OH)3 (basicity)r(\text{La}^{3+}) > \ldots > r(\text{Lu}^{3+});\quad \text{La(OH)}_3 > \ldots > \text{Lu(OH)}_3\ \text{(basicity)}

Worked example

Arrange Sm³⁺, La³⁺ and Er³⁺ in decreasing ionic radius, and name the weakest base among their hydroxides.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 3Transition and Inner Transition ElementsMODERATE
Identify a weakest base from following

[Q78 · 22 April Shift I · 2025]

Picking Yb as the smallest ion

Yb is near the end but Lu is after it: when both appear, the smallest Ln³⁺ is Lu³⁺. Yb wins only the ionisation-enthalpy question.

Concept 4 of 4

Lanthanoid Compounds and General Properties

Intuition

Because the common state is +3, lanthanoid compounds follow the Ln³⁺ formula: the hydroxide is Ln(OH)₃, the oxide Ln₂O₃, the halide LnX₃. Heated with carbon at about 2773 K they give carbides LnC₂. The metals are soft, silvery and good conductors; their compounds are strongly paramagnetic (except f⁰ and f¹⁴); their large ions take coordination numbers above six. Not all are stable nuclei: promethium is radioactive.

Definition

  • Formulas: hydroxide Ln(OH)3\text{Ln(OH)}_3; oxide Ln2O3\text{Ln}_2\text{O}_3; halide LnX3\text{LnX}_3; carbide (with C at high temperature) LnC2\text{LnC}_2; with water → Ln(OH)3+H2\text{Ln(OH)}_3 + \text{H}_2; with N2\text{N}_2 → LnN.
  • True: soft metals; good conductors of heat and electricity; coordination number usually greater than six; strongly paramagnetic.
  • NOT true: 'bad conductors'; 'all are non-radioactive' (promethium, Pm, is radioactive).

Common lanthanoid compounds

Ln3+: Ln(OH)3, Ln2O3, LnX3;Ln+2C→ΔLnC2\text{Ln}^{3+}:\ \text{Ln(OH)}_3,\ \text{Ln}_2\text{O}_3,\ \text{LnX}_3;\quad \text{Ln} + 2\text{C} \xrightarrow{\Delta} \text{LnC}_2

Worked example

Write the formulas of the oxide and the chloride of gadolinium.
Practice this conceptself-check · 3 quick reps

From the bank · past-year question

Example 4Transition and Inner Transition ElementsEASY
Which from following properties of lanthanoids is NOT true?

[Q67 · 4th May Shift 2 · 2023]

Assuming every lanthanoid is stable

Promethium (Z = 61) has no stable isotope. 'All lanthanoids are non-radioactive' is the false statement the paper keys.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • 4f Configurations and the +2 and +4 States

    f electrons in Ln³⁺

    nf(Ln3+)=Z−57;unpaired={nfnf≤714−nfnf>7n_f(\text{Ln}^{3+}) = Z - 57;\quad \text{unpaired} = \begin{cases} n_f & n_f \le 7 \\ 14 - n_f & n_f > 7 \end{cases}
  • The Lanthanoid Contraction: Size, Basicity and Ionisation Enthalpy

    Trends along the lanthanoids

    r(La3+)>…>r(Lu3+);La(OH)3>…>Lu(OH)3 (basicity)r(\text{La}^{3+}) > \ldots > r(\text{Lu}^{3+});\quad \text{La(OH)}_3 > \ldots > \text{Lu(OH)}_3\ \text{(basicity)}
  • Lanthanoid Compounds and General Properties

    Common lanthanoid compounds

    Ln3+: Ln(OH)3, Ln2O3, LnX3;Ln+2C→ΔLnC2\text{Ln}^{3+}:\ \text{Ln(OH)}_3,\ \text{Ln}_2\text{O}_3,\ \text{LnX}_3;\quad \text{Ln} + 2\text{C} \xrightarrow{\Delta} \text{LnC}_2

Reference tables (1)

Which Element Is a Lanthanoid, Which an Actinoid2 rows
SeriesZMembers to recognise
Lanthanoids (4f)57–71La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu
Actinoids (5f)89–103Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr
All actinoids are radioactive.
Tm, Pm, Sm are lanthanoids; Cm, Am, Np are actinoids — the look-alike pairs the options use.

Watch out for (4)

Drill every past-year question on this subtopic

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