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SSC CGL Reasoning · Mathematical Operations

Hidden Operation Rules

A made-up symbol stands for a rule. Either the stem states the rule, or it shows worked examples and you find the rule, test it on every example, and only then use it.

Why this matters

Fifty-six questions in the bank, 33 EASY and 23 MODERATE, and 49 of them come from the 2025 shifts. Most show two examples of a symbol and ask for a third; a few state the rule, ask for the odd one out, or give chains of operations on sets of numbers.

Concept 1 of 4: A rule you are given

Sometimes the stem spells the rule out, such as a%b=a+b+aba \% b = a + b + ab. Then there is nothing to find: put each number in its place and work it out.

Definition

  • The first number is aa and the second is bb. Write them into the rule.
  • Work out the result in BODMAS order.
  • If the stem asks which pair gives a stated value, put each option's pair into the rule and keep the one that matches.
  • A rule need not give the same answer both ways round: with a&b=ab−aa \& b = ab - a, 4&6=204 \& 6 = 20 but 6&4=186 \& 4 = 18.

Worked example

If a#b=2a+b2a \# b = 2a + b^2, find 5#35 \# 3.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 26 Sep 2025, Shift 1 · Q4Easy

Example 1 · Mathematical Operations · Hidden Operation Rules

If A & B = A ×\times B - A, what is 7 & 5?

Putting the numbers in the wrong places

The first number is aa. With a@b=a−2ba @ b = a - 2b, 9@2=59 @ 2 = 5 but 2@9=−162 @ 9 = -16, so keep the order the question prints.

Concept 2 of 4: Finding the rule from examples

Two or three examples of a made-up symbol are a puzzle with a short list of usual answers. Try the simple rules on the first example, keep one that fits, and test it on every other example before you use it.

Definition

Try the rules in this order on the first example:

  • One operation: a+ba + b, a×ba \times b, a−ba - b, a÷ba \div b.
  • Squares and powers: a2+b2a^2 + b^2, (a+b)2(a + b)^2, aba^b, a2+ba^2 + b, a2−ba^2 - b.
  • Mixed: 2(a+b)2(a + b), 2ab2ab, ab+a+bab + a + b, ab+aab + a, ab+bab + b, a(a+b)a(a + b), (a+b)×b(a + b) \times b, (a−b)3(a - b)^3.
  • A result next to a square or cube points to one: 50 is 72+17^2 + 1, 343 is 737^3.
  • Test the rule on every example. A rule that fits one example is only a guess.
  • When two rules fit every example, work out both. If they agree, the answer is safe. If they land on two different options, the question is ambiguous; prefer the rule that uses both numbers.

Common hidden rules

a2+b2(a+b)2aba2+bab+a+b=(a+1)(b+1)−1a^2 + b^2 \qquad (a + b)^2 \qquad a^b \qquad a^2 + b \qquad ab + a + b = (a + 1)(b + 1) - 1
  • aathe number before the symbol
  • bbthe number after the symbol

Worked example

If 6@1=376 @ 1 = 37 and 2@4=202 @ 4 = 20, find 3@53 @ 5.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 16 Sep 2025, Shift 2 · Q22Moderate

Example 2 · Mathematical Operations · Hidden Operation Rules

If 3 @ 4 = 19, 5 @ 6 = 41, then what is 6 @ 7?

Stopping after one example

6@2=126 @ 2 = 12 fits a×ba \times b and also a+b+4a + b + 4. Only the second example tells them apart, so test every example before you use a rule.

Missing a second rule that fits

6∗1=426 * 1 = 42 and 3∗4=213 * 4 = 21 fit both a(a+b)a(a + b) and 7a7a, because a+b=7a + b = 7 in each. For 5∗35 * 3 they give 40 and 35. When two rules fit, work out both before you choose.

Concept 3 of 4: The odd one out among four results

Four results of one symbol are printed and three follow the same rule. Find the rule three of them share; the one that breaks it is the answer.

Definition

  • Try the simple rules on each option in turn: +, −, ×, ÷, then the rules from the last concept.
  • The rule must fit exactly three options. If it fits all four, or only two, try the next rule.
  • Fast route: when all four results are the same number, ask what each pair of numbers does to reach it; the one that needs a different step is out.

Worked example

Find the odd one out: (a) 9@3=129 @ 3 = 12 (b) 8@6=148 @ 6 = 14 (c) 7@4=37 @ 4 = 3 (d) 5@5=105 @ 5 = 10
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 15 Sep 2025, Shift 2 · Q9Moderate

Example 3 · Mathematical Operations · Hidden Operation Rules

Find the odd one out:

Settling for a rule that fits two

A rule that fits only two of the four options leaves two candidates. Keep trying until one rule fits exactly three.

Concept 4 of 4: Chains of operations on number sets

Each set is a chain: the same steps take the first number to the second, the second to the third, and so on. Read the steps from one set, confirm them on the other, then walk each option through them.

Definition

  • Write the step under each link of the first set: ×2\times 2, +10+ 10, square, and so on.
  • Confirm the same steps on the second set. If a step does not match, look for one that depends on the first number, such as ‘take away the first number’.
  • Walk each option through the steps. The first wrong step rules it out; options are often built to pass the first step and fail a later one.
  • Work on whole numbers only: SSC's note forbids splitting 13 into 1 and 3.

Worked example

In the sets 6, 18, 13, 26 and 9, 27, 22, 44 the same steps link the numbers. Which follows them: (a) 4, 12, 7, 14 (b) 5, 15, 10, 25 (c) 7, 21, 15, 30 (d) 8, 16, 11, 22?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2024 · Tier I, 11 Sep 2024, Shift 3 · Q24Moderate

Example 4 · Mathematical Operations · Hidden Operation Rules

Two sets of numbers are given below. In each set of numbers, certain mathematical operation(s) on the first number result(s) in the second number. Similarly, certain mathematical operation(s) on the second number result(s) in the third number and so on. Which of the given options follows the same set of operations as in the given sets? (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g. 13 – Operations on 13 such as adding/subtracting/multiplying to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed.) 14 – 196 – 186 – 172; 15 – 225 – 215 – 200

Checking only the first step

Wrong options usually pass the first step and break at the second or third. Walk every option through every step.

Splitting a number into digits

The steps act on whole numbers. Adding the digits of 13 to get 4 is not allowed in these questions.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (1)

  • Finding the rule from examples

    Common hidden rules

    a2+b2(a+b)2aba2+bab+a+b=(a+1)(b+1)−1a^2 + b^2 \qquad (a + b)^2 \qquad a^b \qquad a^2 + b \qquad ab + a + b = (a + 1)(b + 1) - 1

Watch out for (6)

Test yourself on Mathematical Operations

20 past SSC CGL questions from this chapter, timed at 12 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.