Playbook
Binomial Theorem
The general term does half the work, coefficient sums the other half. Nearly half its questions have numeric answers, so accuracy matters more than speed here.
- Questions in the bank
- 165
- q/paper in 2025–26
- 1.05
- Numeric answer
- 45%
- Notes pages
- 8
Tier: Core
When you’ll see it
A power of a bracket: one coefficient, the constant term, a sum of C(n, r) terms, or the remainder of a large power.
How this chapter is tested
The general term T(r + 1) = C(n, r) aⁿ⁻ʳ bʳ does most of the chapter's work. Set the power of x to what is asked, solve for r, and read the coefficient. Consecutive coefficients, products of brackets and rational terms are the same step with a different condition on r.
The second half is sums of binomial coefficients. Substitute x = 1, −1 or a complex root into an expansion; differentiate it for r·C(n, r); integrate it for C(n, r)/(r + 1); multiply two expansions for a product of coefficients. Once you name which of these a sum is, it closes in two lines. The time goes on naming it.
Most answers are whole numbers, so the chapter suits numeric-answer questions. Remainders of large powers write the base as a multiple of the divisor plus or minus 1 and expand. The coefficient sums share their tools with Sequences and Series and with Definite Integration.
The sub-skills
The distinct skills inside the chapter, in the order to learn them.
The general term
T(r + 1) = C(n, r) aⁿ⁻ʳ bʳ; set the power of x and solve for r. Simplify the bracket first when it factors.
Consecutive coefficients and special terms
C(n, r)/C(n, r − 1) = (n − r + 1)/r turns three consecutive coefficients into two linear equations; middle and end terms by symmetry.
Products and three-term brackets
A coefficient of a product is a short sum of products; a three-term bracket is factored or expanded with the multinomial term.
Rational terms and integral parts
A term is rational when both exponents are whole; (a + √b)ⁿ + (a − √b)ⁿ is an integer.
Coefficient sums
x = 1 gives the sum of all coefficients, x = −1 the alternating sum; differentiate for Σ r·C(n, r) = n·2ⁿ⁻¹.
Fractions and products of coefficients
Integrate for C(n, r)/(r + 1); Σ C(m, r) C(n, k − r) = C(m + n, k).
Hockey stick and geometric sums
C(r, r) + C(r + 1, r) + … + C(n, r) = C(n + 1, r + 1); a sum of powers of (1 + x) is a geometric series.
Remainders and divisibility
Write the base as kd ± 1, expand, and only the last term survives division by d.
Traps to expect
Distractor shapes this chapter reuses. The Traps page covers the ones that cut across chapters.
The index is r + 1
The term containing bʳ is the (r + 1)-th. 'The 7th term' means r = 6.
The sign of the second term
In (x − 1/x)ⁿ each term carries (−1)ʳ. Dropping it flips the sign of every odd-r coefficient.
Only one exponent checked
For a rational term in (a^(1/p) + b^(1/q))ⁿ, both (n − r)/p and r/q must be whole numbers.
A left-over factor
2¹⁰⁰ = 2 · 8³³, so its remainder on division by 7 is 2, not 1. A factor outside the bracket stays in the answer.
Learn it before you drill it
This chapter has full teaching notes — foundations, worked examples, self-checks and a mastery check for each page. Read the notes once, then drill page by page below.
Binomial Theorem notesDrill every Binomial Theorem question
165 questions from the bank, across 8 subtopics.
Drill one subtopic at a time
The 8 subtopics, in teaching order.
- The General TermDrill The General Term
- Consecutive Coefficients and Special TermsDrill Consecutive Coefficients and Special Terms
- Products and Multinomial ExpansionsDrill Products and Multinomial Expansions
- Rational and Integral TermsDrill Rational and Integral Terms
- Coefficient Sums by Substitution and DifferentiationDrill Coefficient Sums by Substitution and Differentiation
- Sums with Fractions and Products of CoefficientsDrill Sums with Fractions and Products of Coefficients
- Sums of Expansions: Hockey Stick and Geometric SeriesDrill Sums of Expansions: Hockey Stick and Geometric Series
- Remainders and DivisibilityDrill Remainders and Divisibility
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