Playbook
Definite Integration
Direct evaluation and piecewise integrands carry much of it; the a + b − x property is the time-saver when a direct attack looks hopeless.
- Questions in the bank
- 196
- q/paper in 2025–26
- 1.30
- Numeric answer
- 33%
- Notes pages
- 7
Tier: Core
When you’ll see it
An integral with limits, especially one that looks impossible directly, carries [x], {x} or |x|, has a variable limit, or is a limit of a long sum.
How this chapter is tested
Direct evaluation — one good substitution, parts or partial fractions — and piecewise integrands with [x], {x} or |x| carry much of the chapter. Piecewise questions are routine once the interval is split where the formula changes.
The property pages save the most time. When a direct attack looks hopeless, write the integral again with x → a + b − x and add the two forms. Over −a to a, drop the odd part; a denominator 1 + bˣ pairs with its reflection and halves the integral of an even numerator. Spotting the pattern is the whole skill.
Leibniz's rule turns an integral equation into a differential equation, which links the chapter to differential equations. Limits of sums become an integral through (1/n) Σ f(k/n). Reduction formulas and Beta integrals ask for a relation between members of a family, not a single value.
The sub-skills
The distinct skills inside the chapter, in the order to learn them.
Evaluating directly
Substitute and change the limits; integrate by parts and work out the boundary term; split into partial fractions.
The a + b − x property
∫ from a to b of f(x) dx equals ∫ from a to b of f(a + b − x) dx; add the two forms. x → 1/x does the same on 1/a to a.
Odd, even and periodic integrands
On −a to a odd parts vanish and even parts double; over n whole periods the integral is n times one period.
Greatest integer, modulus and max–min
Split at the integers for [x], at the roots for |f(x)|, and where the two curves cross for max or min.
Leibniz's rule and integral equations
d/dx of ∫ from g(x) to h(x) of f(t) dt is f(h)h′ − f(g)g′; an integral with constant limits is an unknown constant.
Reduction formulas and Beta integrals
Link Iₙ to Iₙ₋₁ by parts; ∫ from 0 to 1 of x^(m − 1)(1 − x)^(n − 1) dx is B(m, n).
Limits of sums
lim (1/n) Σ f(k/n) = ∫ from 0 to 1 of f(x) dx, with the upper limit set by the range of k.
Traps to expect
Distractor shapes this chapter reuses. The Traps page covers the ones that cut across chapters.
Old limits after a substitution
With t = tan x, x = π/2 becomes t → ∞; with t = tan(x/2) it becomes t = 1. Keeping the old limits is the most common slip.
The greatest integer of a negative
[−0.3] = −1, not 0. On an interval below zero, [x] is the next integer to the left.
The wrong period
|sin x| repeats every π, not 2π. Using the longer period halves the number of copies and halves the answer.
The missing chain factor
An upper limit x² brings a factor 2x in Leibniz's rule, and the lower limit enters with a minus sign.
Learn it before you drill it
This chapter has full teaching notes — foundations, worked examples, self-checks and a mastery check for each page. Read the notes once, then drill page by page below.
Definite Integration notesDrill every Definite Integration question
196 questions from the bank, across 7 subtopics.
Drill one subtopic at a time
The 7 subtopics, in teaching order.
- Evaluating by Substitution, Parts and Partial FractionsDrill Evaluating by Substitution, Parts and Partial Fractions
- The a + b - x Property and Other SymmetriesDrill The a + b - x Property and Other Symmetries
- Odd, Even and Periodic IntegrandsDrill Odd, Even and Periodic Integrands
- Greatest Integer, Modulus and Max-Min IntegrandsDrill Greatest Integer, Modulus and Max-Min Integrands
- Integral Equations and Leibniz's RuleDrill Integral Equations and Leibniz's Rule
- Reduction Formulas and Beta IntegralsDrill Reduction Formulas and Beta Integrals
- Limits of Sums as IntegralsDrill Limits of Sums as Integrals
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