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AFCAT Numerical Ability · Average

One Value In, Out or Changed

Turn the old average into a total, add or take away the value that changed, and divide by the right count: for a newcomer, someone who leaves, a member who is replaced and a value that was misread.

Why this matters

Six of the chapter's thirteen AFCAT past-year questions are on this page, from 2015 to 2019: a man replaced, a misread weight, a team's ages. Almost all of the page is EASY. The marks go when the count is not updated, or when a misread value is corrected in the wrong direction.

Concept 1 of 5: One more value: a new day, a teacher, a manager

A new value joins the total and the count grows by one. If the new value is above the average it pulls the average up, but by much less than the gap.

Definition

  • New total = old total + new value; new count = n+1n + 1.
  • Shortcut: the average moves by x−An+1\dfrac{x - A}{n + 1}, up if the new value xx is above the old average AA, down if below.
  • 'Including the teacher' or 'the next day' is the same move.

One value added

new average=nA+xn+1\text{new average} = \dfrac{nA + x}{n + 1}

Worked example

A worker's average output over 9 days is 40 units. On the 10th day he makes 70. Find his new average.
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The same idea in a practice question:

Practice questionEasy

Example 1 · Average · Adding, Removing or Replacing a Value

The average temperature of a city for 66 days was 28°C28°C. If the temperature on the seventh day was 35°C35°C, what is the average temperature for all 77 days?

The count goes up too

A salary of ₹60,000 added to 9 people averaging ₹40,000 gives (3,60,000+60,000)÷10=₹42,000(3{,}60{,}000 + 60{,}000) \div 10 = ₹42{,}000. Dividing by 9 again gives ₹46,667.

Concept 2 of 5: One value removed

Take the value out of the total and one off the count. Removing a value above the average pulls the average down; removing one below it pushes the average up.

Definition

  • New total = nA−xnA - x; new count = n−1n - 1.
  • The average falls by x−An−1\dfrac{x - A}{n - 1} when xx is above the average, and rises when xx is below it.
  • Two or three values removed: take out their sum and reduce the count by that many.

One value removed

new average=nA−xn−1\text{new average} = \dfrac{nA - x}{n - 1}

Worked example

The average of 10 numbers is 24. The number 42 is removed. Find the new average.
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The same idea in a practice question:

Practice questionEasy

Example 2 · Average · Adding, Removing or Replacing a Value

Six friends have an average height of 167 cm. A boy with height 162 cm leaves the group. Find the average height of the group now.

A low value leaving raises the average

From 11 values averaging 50, removing a 30 lifts the average to (550−30)÷10=52(550 - 30) \div 10 = 52.

Concept 3 of 5: Finding the value that joined or left

If one newcomer lifts the average of nn people by dd, the newcomer must supply the new average for themselves plus dd for each of the nn others.

Definition

  • Joiner: x=(n+1)×new average−n×old averagex = (n + 1) \times \text{new average} - n \times \text{old average}. Shortcut: x=new average+n×risex = \text{new average} + n \times \text{rise}.
  • Leaver: x=n×old average−(n−1)×new averagex = n \times \text{old average} - (n - 1) \times \text{new average}. Shortcut: x=old average+(n−1)×fallx = \text{old average} + (n - 1) \times \text{fall}.
  • If the average falls when someone joins, the 'rise' is negative and the newcomer is below the new average.

The newcomer

x=(n+1)A′−nA=A′+n(A′−A)x = (n + 1)A' - nA = A' + n(A' - A)

Worked example

The average age of 19 students is 12. When the teacher is included, the average becomes 13.5. Find the teacher's age.
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The same idea in a practice question:

Practice questionEasy

Example 3 · Average · Adding, Removing or Replacing a Value

The average weight of 21 boys was recorded as 64 kg. If the weight of the teacher was added, the average increased by 1 kg. What was the teacher's weight?

The newcomer pays for everyone

If 20 people average 50 and a newcomer lifts it to 52, the newcomer is 52+20×2=9252 + 20 \times 2 = 92, not 50+20×2=9050 + 20 \times 2 = 90.

Concept 4 of 5: Replacing a member

A replacement keeps the count the same, so the whole change in the total is spread over all nn members. A rise of dd in the average means the newcomer is ndnd more than the person replaced.

Definition

  • Count unchanged: new value − old value =n×= n \times change in the average.
  • Two replaced by two: the two newcomers' total is the two leavers' total plus n×n \times the change; halve it for their average.
  • Ages in years and months: turn everything into months first.

One member replaced

xnew=xold+n dx_{\text{new}} = x_{\text{old}} + n\,d

Worked example

The average weight of 8 boys rises by 1.5 kg when a boy of 46 kg is replaced by a new boy. Find the new boy's weight.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

AFCAT · 2015 · AFCAT (I) 2015 — Numerical Ability · 02-214Easy

Example 4 · Average · Adding, Removing or Replacing a Value

The average weight of 5 men is increased by 2 kg when one of the men whose weight is 60 kg is replaced by a new man. The weight of the new man is

No one was added

A swap changes no count. A rise of 1.5 in the average of 8 means the total rose by 8×1.5=128 \times 1.5 = 12, not 9×1.5=13.59 \times 1.5 = 13.5.

Concept 5 of 5: A value misread or miscopied

The wrong value sat in the total in place of the right one. Swap it back: the total moves by the difference, and the average by the difference over the count.

Definition

  • Correct total = wrong total − wrong value + right value.
  • The average changes by right−wrongn\dfrac{\text{right} - \text{wrong}}{n}: up if the right value is bigger, down if smaller.
  • Several errors: add up the differences first, then divide once.
  • Reversed digits: 53 written as 35 is an error of 18. Any two-digit reversal is off by 9 times the difference of the digits.

Correcting one value

correct average=A+right value−wrong valuen\text{correct average} = A + \dfrac{\text{right value} - \text{wrong value}}{n}

Worked example

The average of 40 numbers was found to be 52. Later, 64 was found to have been copied as 40. Find the correct average.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

AFCAT · 2019 · AFCAT (I) 2019 — Numerical Ability · 02-204Easy

Example 5 · Average · Adding, Removing or Replacing a Value

The average weight of a group of 20 boys was calculated to be 89.4 kg and it was later discovered that one weight was misread as 78 kg instead of 87 kg. The correct average weight is

Which way round

If 64 was written as 46, the total was 18 too small and the true average is higher. Subtracting instead moves the average the wrong way by twice as much.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (5)

  • One more value: a new day, a teacher, a manager

    One value added

    new average=nA+xn+1\text{new average} = \dfrac{nA + x}{n + 1}
  • One value removed

    One value removed

    new average=nA−xn−1\text{new average} = \dfrac{nA - x}{n - 1}
  • Finding the value that joined or left

    The newcomer

    x=(n+1)A′−nA=A′+n(A′−A)x = (n + 1)A' - nA = A' + n(A' - A)
  • Replacing a member

    One member replaced

    xnew=xold+n dx_{\text{new}} = x_{\text{old}} + n\,d
  • A value misread or miscopied

    Correcting one value

    correct average=A+right value−wrong valuen\text{correct average} = A + \dfrac{\text{right value} - \text{wrong value}}{n}

Watch out for (5)

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