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AFCAT Numerical Ability · Decimal and Fractions

Fraction Arithmetic, Fraction Word Problems and Simplification

Work with fractions and mixed numbers, find a whole from a fraction of it, and simplify long expressions in the right order or with an algebraic shortcut.

Why this matters

Five of the chapter's AFCAT past-year questions are here, from 2016, 2017 and 2019: two fraction word problems and three simplifications. The marks go on the order of operations ('of' first, then division and multiplication from left to right) and on dividing by the wrong fraction in a word problem.

Concept 1 of 6: Operations on fractions and mixed numbers

Mixed numbers are awkward to multiply or divide, so turn them into improper fractions first. Then multiply straight across, and divide by multiplying by the flipped fraction.

Definition

  • Mixed to improper: 213=2×3+13=732\tfrac13 = \tfrac{2 \times 3 + 1}{3} = \tfrac73.
  • Add or subtract over the LCM of the denominators. With mixed numbers, the whole parts can be added separately.
  • Multiply: tops together, bottoms together, cancelling first.
  • Divide: multiply by the reciprocal of the divisor.
  • 'Of' means multiply: 23\tfrac23 of 60 is 40.

Dividing by a fraction

ab÷cd=ab×dc\dfrac ab \div \dfrac cd = \dfrac ab \times \dfrac dc

Worked example

Find 213×127÷1122\tfrac13 \times 1\tfrac27 \div 1\tfrac12.
Practice this conceptself-check · 4 quick reps

The same idea in a practice question:

Practice questionModerate

Example 1 · Decimal and Fractions · Fractions and Simplification

415×427÷3134\frac{1}{5} \times 4\frac{2}{7} \div 3\frac{1}{3} is equal to

Mixed numbers multiply only as improper fractions

212×212=52×52=6142\tfrac12 \times 2\tfrac12 = \tfrac52 \times \tfrac52 = 6\tfrac14. Multiplying the wholes and the halves apart gives 4144\tfrac14.

Of means times

35\tfrac35 of 23\tfrac23 is 35×23=25\tfrac35 \times \tfrac23 = \tfrac25, never 35−23\tfrac35 - \tfrac23.

Concept 2 of 6: Finding the whole from a fraction of it

If a known amount is a fraction of something, the whole is the amount divided by that fraction. When a tank goes from one fraction full to another, the amount poured in is the difference of the two fractions.

Definition

  • 'A fraction ff of the whole is AA' gives whole =A÷f= A \div f.
  • A level that changes from f1f_1 to f2f_2 because AA litres went in or out: AA is (f2−f1)(f_2 - f_1) of the capacity.
  • 'One fraction of a number is AA more than another fraction of it': AA is the difference of the fractions.
  • Once the whole is known, any other fraction of it follows.

Whole from a part

whole=amountthe fraction it is (or the difference of two fractions)\text{whole} = \dfrac{\text{amount}}{\text{the fraction it is (or the difference of two fractions)}}

Worked example

A drum is 25\tfrac25 full. After 36 L is poured in, it is 710\tfrac{7}{10} full. Find its capacity.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

AFCAT · 2017 · AFCAT (II) 2017 — Numerical Ability · 01-310Easy

Example 2 · Decimal and Fractions · Fractions and Simplification

15\frac{1}{5}th tank is full and if 22 L fuel poured in, then 34\frac{3}{4}th tank is full. Find the capacity of tank.

Divide by the difference, not by either fraction

In the drum above, 36÷71036 \div \tfrac{7}{10} is about 51 L and is wrong: the 36 L filled only the gap between the two levels.

Remains means the new level

'After 30 L is drawn, half remains' puts the level at 12\tfrac12. The fraction drawn out is the old level minus 12\tfrac12.

Concept 3 of 6: The wrong-operation problem

Someone was told to do one thing to a number and did another. Both results are fractions of the same unknown number, so their difference is a fraction of it too, and that difference is given.

Definition

  • Write both results as multiples of xx. Dividing by pq\tfrac pq is multiplying by qp\tfrac qp.
  • Subtract the smaller multiple from the larger and set it equal to the given difference.
  • Solve for xx, then read the question again: it may want the number, or the correct result.

Wrong result against right result

(qp−pq)x=d(divided by pq instead of multiplying)\left(\dfrac{q}{p} - \dfrac{p}{q}\right) x = d \quad (\text{divided by } \tfrac pq \text{ instead of multiplying})

Worked example

A student was to multiply a number by 45\tfrac45 but divided it by 45\tfrac45, and got 36 more than the right answer. Find the number.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

AFCAT · 2016 · AFCAT (II) 2016 — Numerical Ability · 01-312Moderate

Example 3 · Decimal and Fractions · Fractions and Simplification

In an examination, a student was asked to find 314\frac{3}{14} of a certain number. By mistake, he found 34\frac{3}{4} of it. His answer was 150 more than the correct answer. Find the number.

Dividing by a fraction flips it

Dividing by 45\tfrac45 multiplies by 54\tfrac54, so the wrong result is the larger one. Writing it as 45x\tfrac45 x again makes the difference zero.

Answer what is asked

In 'multiplied by 5 instead of dividing, and got 125', the number is 25 but the correct answer is 25÷5=525 \div 5 = 5. Both are usually among the options.

Concept 4 of 6: Order of operations (BODMAS)

A long expression has one value only because everyone follows the same order: brackets from the inside out, then 'of', then division and multiplication, then addition and subtraction.

Definition

  • Brackets, innermost first: (  )( \; ), then {  }\{ \; \}, then [  ][ \; ].
  • Of next: 8÷128 \div \tfrac12 of 4=8÷2=44 = 8 \div 2 = 4, while 8÷12×4=648 \div \tfrac12 \times 4 = 64.
  • Division and multiplication as they come, left to right.
  • Addition and subtraction as they come, left to right.
  • A minus sign in front of a bracket changes the sign of everything inside when the bracket is removed.
  • Decimals follow the same order: multiply and divide before you add.

Order of operations

brackets→of→÷ and ×→+ and −\text{brackets} \to \text{of} \to \div \text{ and } \times \to + \text{ and } -

Worked example

Simplify 60−[14−{9−(3+2)}]+18÷2×360 - [14 - \{9 - (3 + 2)\}] + 18 \div 2 \times 3.
Practice this conceptself-check · 4 quick reps

The same idea in a practice question:

Practice questionModerate

Example 4 · Decimal and Fractions · Fractions and Simplification

Simplify 1035÷[(34) of (71+65)−1534]1035 \div \left[\left(\frac{3}{4}\right) \text{ of } (71 + 65) - 15\frac{3}{4}\right].

Division and multiplication go left to right

36÷6×3=6×3=1836 \div 6 \times 3 = 6 \times 3 = 18. Doing the multiplication first gives 36÷18=236 \div 18 = 2.

A minus before a bracket flips the signs inside

20−(8−x)=12+x20 - (8 - x) = 12 + x, not 12−x12 - x.

Concept 5 of 6: Complex and continued fractions

A fraction with fractions above and below its line is two separate sums. Finish the top, finish the bottom, then divide. A continued fraction is the same idea stacked, so start at the bottom and climb.

Definition

  • Simplify the numerator to one fraction and the denominator to one fraction.
  • Then divide: multiply the top by the reciprocal of the bottom.
  • Inside either part, BODMAS applies, and 'of' means multiply.
  • Continued fraction: work out the lowest level first, flip it, add the level above, and repeat.

A fraction over a fraction

a/bc/d=ab×dc\dfrac{a / b}{c / d} = \dfrac ab \times \dfrac dc

Worked example

Simplify 12+34213−12\dfrac{\tfrac12 + \tfrac34}{2\tfrac13 - \tfrac12}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

AFCAT · 2019 · AFCAT (I) 2019 — Numerical Ability · 01-304Moderate

Example 5 · Decimal and Fractions · Fractions and Simplification

114÷112(115+1−910)\cfrac{1\frac{1}{4} \div 1\frac{1}{2}}{\left(\frac{1}{15} + 1 - \frac{9}{10}\right)} is equal to

Never cancel across a plus sign

6+82=7\dfrac{6 + 8}{2} = 7. Cancelling the 2 into the 6 alone, to get 3+83 + 8, treats a sum as if it were a product.

A continued fraction is read from the bottom

In 1+11+131 + \cfrac{1}{1 + \cfrac13}, the 1+131 + \tfrac13 at the bottom must be found first. Starting at the top adds the wrong things together.

Concept 6 of 6: Algebraic shortcuts in simplification

When an expression has the shape of an identity, the arithmetic collapses. a2−b2a^2 - b^2 with awkward decimals becomes (a−b)(a+b)(a - b)(a + b), usually two round numbers.

Definition

  • a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b).
  • a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 and a2−2ab+b2=(a−b)2a^2 - 2ab + b^2 = (a - b)^2.
  • a3−b3a2+ab+b2=a−b\dfrac{a^3 - b^3}{a^2 + ab + b^2} = a - b and a3+b3a2−ab+b2=a+b\dfrac{a^3 + b^3}{a^2 - ab + b^2} = a + b.
  • If a+b+c=0a + b + c = 0, then a3+b3+c3−3abc=0a^3 + b^3 + c^3 - 3abc = 0.
  • A common factor comes out: ab−ac=a(b−c)ab - ac = a(b - c).

Difference of squares

a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b)

Worked example

Find 5.5×5.5−2.5×2.50.3\dfrac{5.5 \times 5.5 - 2.5 \times 2.5}{0.3}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

AFCAT · 2019 · AFCAT (II) 2019 — Numerical Ability · 01-302Easy

Example 6 · Decimal and Fractions · Fractions and Simplification

3.25×3.20−3.20×3.050.064\frac{3.25 \times 3.20 - 3.20 \times 3.05}{0.064} is equal to

The zero needs a + b + c = 0

For a=1a = 1, b=2b = 2, c=3c = 3, a3+b3+c3−3abc=1+8+27−18=18a^3 + b^3 + c^3 - 3abc = 1 + 8 + 27 - 18 = 18, not 0. Check the sum before using the shortcut.

Look for the shape before multiplying

Squaring 5.55.5 and 2.52.5 by hand works but costs time and invites a slip. A difference of two squares, or a repeated factor in two products, is the signal to factor first.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (6)

  • Operations on fractions and mixed numbers

    Dividing by a fraction

    ab÷cd=ab×dc\dfrac ab \div \dfrac cd = \dfrac ab \times \dfrac dc
  • Finding the whole from a fraction of it

    Whole from a part

    whole=amountthe fraction it is (or the difference of two fractions)\text{whole} = \dfrac{\text{amount}}{\text{the fraction it is (or the difference of two fractions)}}
  • The wrong-operation problem

    Wrong result against right result

    (qp−pq)x=d(divided by pq instead of multiplying)\left(\dfrac{q}{p} - \dfrac{p}{q}\right) x = d \quad (\text{divided by } \tfrac pq \text{ instead of multiplying})
  • Order of operations (BODMAS)

    Order of operations

    brackets→of→÷ and ×→+ and −\text{brackets} \to \text{of} \to \div \text{ and } \times \to + \text{ and } -
  • Complex and continued fractions

    A fraction over a fraction

    a/bc/d=ab×dc\dfrac{a / b}{c / d} = \dfrac ab \times \dfrac dc
  • Algebraic shortcuts in simplification

    Difference of squares

    a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b)

Watch out for (12)

Drill the questions on this topic

33 questions from the bank, with cart and Word export.