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AFCAT Numerical Ability · Surface Area and Volume

Cube, Cuboid, Prism and Pyramid

Volume, surface area and diagonal of a cube and a cuboid, the open tank and its wetted surface, how a cube's measures scale, and the base area rule for prisms and pyramids.

Why this matters

Most questions here are one formula and one line of arithmetic, so the marks go on reading the stem: total or lateral surface, a closed box or an open tank, a face diagonal or the space diagonal. All six prism and pyramid questions are marked HARD, yet each is base area times height, with a third for the pyramid.

Concept 1 of 4: Cube: volume, surface and diagonal

A cube is six equal square faces. Its volume is the edge used three times, its surface is six squares, and the walls alone (no top, no bottom) are four squares.

Definition

  • Volume a3a^3, total surface 6a26a^2, lateral surface (four walls) 4a24a^2.
  • Face diagonal a2a\sqrt 2; space diagonal (corner to opposite corner) a3a\sqrt 3. So two corners of a cube are aa, a2a\sqrt 2 or a3a\sqrt 3 apart.
  • Working back: from the volume take the cube root; from the total surface divide by 6, then take the square root.
  • With total surface SS and volume VV: S3=216a6=216V2S^3 = 216a^6 = 216V^2.

Cube of edge a

V=a3,S=6a2,LSA=4a2,d=a3V = a^3,\quad S = 6a^2,\quad \text{LSA} = 4a^2,\quad d = a\sqrt{3}

Worked example

A cube has edge 7 cm. Find its volume, total surface, lateral surface and space diagonal.
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The same idea in a practice question:

Practice questionEasy

Example 1 · Surface Area and Volume · Cube, Cuboid, Prism and Pyramid

TSA of a cube with volume 125125 cm³ is:

Lateral surface is four faces, not six

A cube of edge 7 cm has total surface 294 cm² but lateral surface 196 cm². Lateral means the walls only.

Divide by 6 before the square root

A total surface of 600 cm² gives a2=100a^2 = 100 and a=10a = 10 cm. Taking 600\sqrt{600} skips the six faces.

Concept 2 of 4: Cuboid: volume, surface, diagonal and the open tank

A cuboid has three pairs of equal rectangles. Its volume is length times breadth times height, and its surface counts each pair twice. The space diagonal is Pythagoras used twice: across the floor, then up.

Definition

  • Volume lbhlbh; total surface 2(lb+bh+hl)2(lb + bh + hl); lateral surface (four walls) 2h(l+b)2h(l + b).
  • Space diagonal l2+b2+h2\sqrt{l^2 + b^2 + h^2}: the longest rod that fits in the box.
  • An open tank or a wetted surface has the floor once and the walls only up to the water: lb+2d(l+b)lb + 2d(l + b) for water dd deep.
  • Cubes of edge aa set in a row of nn make a cuboid na×a×ana \times a \times a. The faces that touch are lost.
  • Given the three face diagonals: they are l2+b2l^2 + b^2, b2+h2b^2 + h^2 and h2+l2h^2 + l^2. Add them and halve to get l2+b2+h2l^2 + b^2 + h^2, then subtract each to get one edge squared.

Cuboid l × b × h

V=lbh,S=2(lb+bh+hl),d=l2+b2+h2V = lbh,\quad S = 2(lb + bh + hl),\quad d = \sqrt{l^2 + b^2 + h^2}
l = 12b = 9h = 881517Pythagoras twicefloor: √(144 + 81) = 15space: √(225 + 64) = 17same as √(l² + b² + h²)

Worked example

A box is 12 cm × 9 cm × 8 cm. Find its volume, total surface, lateral surface and the longest rod that fits inside.
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The same idea in a practice question:

Practice questionEasy

Example 2 · Surface Area and Volume · Cube, Cuboid, Prism and Pyramid

A cistern 6 m long and 4 m wide contains water to a depth of 1.25 m. What is the area of wetted surface?

Lateral surface leaves out top and bottom

A box 12 cm × 9 cm × 8 cm has total surface 552 cm² but lateral surface 336 cm². Read which one the stem asks for.

An open tank has no lid, and wet walls stop at the water

A tank 5 m × 3 m with water 2 m deep has wetted surface 15+2×2×8=4715 + 2 \times 2 \times 8 = 47 m², not the closed box's 62 m².

Concept 3 of 4: Scaling a cube, and comparing a cube with a cuboid

Make every length k times as long and every area becomes k² times as big, every volume k³ times. Two cubes are always the same shape, so their edges, surfaces and volumes follow k, k² and k³.

Definition

  • Edges in the ratio kk: surfaces in k2k^2, volumes in k3k^3.
  • Back from volumes, take the cube root to get the edges; back from surfaces, the square root.
  • An edge up by r%r\% multiplies the volume by (1+r100)3\left(1 + \tfrac{r}{100}\right)^3 and the surface by (1+r100)2\left(1 + \tfrac{r}{100}\right)^2.
  • A cuboid with edges in a given ratio: write them pk,qk,rkpk, qk, rk, set its volume or surface equal to the cube's, and find the cube's edge in kk.

Two cubes of edges a₁ and a₂

S1S2=(a1a2)2,V1V2=(a1a2)3\dfrac{S_1}{S_2} = \left(\dfrac{a_1}{a_2}\right)^2,\quad \dfrac{V_1}{V_2} = \left(\dfrac{a_1}{a_2}\right)^3

Worked example

Two cubes have surfaces in the ratio 25:4925 : 49. Find the ratio of their volumes.
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The same idea in a practice question:

Practice questionHard

Example 3 · Surface Area and Volume · Cube, Cuboid, Prism and Pyramid

Two cubes have volumes in ratio 8:278:27. Ratio of their surface areas is:

Square for area, cube for volume

Cubes with volumes 1:10001 : 1000 have edges 1:101 : 10 and surfaces 1:1001 : 100. The volume ratio is not the surface ratio.

A 10% longer edge is not 30% more volume

1.13=1.3311.1^3 = 1.331, so the volume grows by 33.1%. Adding the percentages three times leaves out the cross terms.

Concept 4 of 4: Prisms and pyramids: base area times height

A prism has the same cross-section all the way along, so its volume is that cross-section times its length; a cuboid is a prism on a rectangle. A pyramid narrows to a point and holds exactly a third of the prism on the same base and height.

Definition

  • Prism: volume = base area × height; lateral surface = perimeter of the base × height.
  • Pyramid: volume = 13\tfrac 13 × base area × height. For a regular pyramid the lateral surface is 12\tfrac 12 × perimeter of the base × slant height.
  • An equilateral triangle of side aa has area 34a2\dfrac{\sqrt 3}{4}a^2; a right triangle has half the product of its legs.
  • A prism and a pyramid of equal base and equal volume: the pyramid is three times as tall.

Base area A, height h

Vprism=Ah,Vpyramid=13AhV_{\text{prism}} = Ah,\quad V_{\text{pyramid}} = \tfrac13 Ah

Worked example

A prism 15 cm long has a right-triangle base with legs 6 cm and 8 cm. Find its volume, and the volume of a pyramid on the same base with the same height.
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The same idea in a practice question:

Practice questionHard

Example 4 · Surface Area and Volume · Cube, Cuboid, Prism and Pyramid

A triangular prism has equilateral triangle base with side 44 cm and height 1010 cm. Volume is:

Do not forget the third

A pyramid on a base of 30 cm² and 12 cm tall holds 120 cm³, not 360 cm³. Only the prism is base times height.

Slant height for faces, vertical height for volume

A square pyramid's triangular faces use the slant height; its volume uses the height straight up from the base.

Summary — formulas & gotchas at a glance

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Formulas (4)

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