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CDS Mathematics · Mensuration 3D

Spheres, Hemispheres & Shells

Volume and surface of a sphere and a hemisphere, hollow shells and their mass, and the circle in which a plane cuts a sphere.

Why this matters

A small page with two formulas to learn and two ideas to use: a shell is the outer sphere minus the inner one, and a plane cutting a sphere gives a right triangle between the centre, the cut and the rim.

Concept 1 of 3: Sphere and hemisphere

A sphere's surface is four times the area of its great circle; its volume is a third of the radius times the surface. A hemisphere has half the volume, but its total surface adds the flat circle.

Definition

  • Sphere: V=43πr3V = \dfrac43\pi r^3, S=4πr2S = 4\pi r^2.
  • Hemisphere: V=23πr3V = \dfrac23\pi r^3; curved surface 2πr22\pi r^2; total 3πr23\pi r^2.
  • Numerically equal surface and volume: 4πr2=43πr34\pi r^2 = \dfrac43\pi r^3 gives r=3r = 3.
  • A sphere cut into nn equal wedges by planes through one diameter: each wedge has 1n\dfrac1n of the curved surface plus two flat semicircles.

Sphere and hemisphere

Vsphere=43πr3,S=4πr2,Vhemi=23πr3V_{\text{sphere}} = \tfrac43\pi r^3, \quad S = 4\pi r^2, \quad V_{\text{hemi}} = \tfrac23\pi r^3

Worked example

Find the total surface area of a solid hemisphere of radius 77 cm. (π=227)(\pi = \tfrac{22}{7})
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2019 · CDS (I) 2019 — Elementary Mathematics · Q67Moderate

Example 1 · Mensuration 3D · Spheres, Hemispheres and Shells

The volume of a hemisphere is 155232 cm3\text{cm}^3. What is the radius of the hemisphere ?

Concept 2 of 3: Hollow shells and their mass

A shell is the outer sphere with the inner sphere removed. Its metal is 43π(R3−r3)\dfrac43\pi(R^3 - r^3); multiply by the density for the mass.

Definition

  • Shell volume =43π(R3−r3)= \dfrac43\pi(R^3 - r^3), with RR the outer and rr the inner radius.
  • Mass == volume ×\times density. In g/cm3^3, the volume must be in cm3^3.
  • Given diameters, halve them first.

Spherical shell

V=43π(R3−r3)V = \tfrac43\pi(R^3 - r^3)

Worked example

A hollow shell has inner radius 44 cm and outer radius 55 cm, made of metal of density 33 g/cm3^3. Find its mass. (π=227)(\pi = \tfrac{22}{7})
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2021 · CDS (II) 2021 — Elementary Mathematics · Q68Moderate

Example 2 · Mensuration 3D · Spheres, Hemispheres and Shells

A hollow spherical shell is made of a metal of density 7 g/cm3^3. If its internal and external radii are 3 cm and 6 cm respectively, then what is the mass of the shell ? (take π=227\pi = \frac{22}{7})

Concept 3 of 3: A plane cutting a sphere

A flat cut through a sphere is a circle. Its radius, its distance from the centre and the sphere's radius form a right triangle. Bowls, pots and water levels in a spherical vessel all use this one triangle.

Definition

  • A plane at distance dd from the centre of a sphere of radius RR cuts a circle of radius ρ=R2−d2\rho = \sqrt{R^2 - d^2}.
  • A bowl filled to depth tt: the water surface is R−tR - t from the centre.
  • A pot of height HH cut from a sphere of radius RR (with H>RH > R): the cut is H−RH - R above the centre.

Circle of a cut

ρ2+d2=R2\rho^2 + d^2 = R^2

Worked example

A spherical bowl of radius 1313 cm holds water to a depth of 88 cm. Find the radius of the water surface.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2025 · CDS (I) 2025 — Elementary Mathematics · Q59Moderate

Example 3 · Mensuration 3D · Spheres, Hemispheres and Shells

A pot is made from a hollow sphere of inner radius 20 cm by cutting its upper portion horizontally. The height of the pot is 30 cm.
What is the inner radius of the circular opening of the pot so formed ?

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • Sphere and hemisphere

    Sphere and hemisphere

    Vsphere=43πr3,S=4πr2,Vhemi=23πr3V_{\text{sphere}} = \tfrac43\pi r^3, \quad S = 4\pi r^2, \quad V_{\text{hemi}} = \tfrac23\pi r^3
  • Hollow shells and their mass

    Spherical shell

    V=43π(R3−r3)V = \tfrac43\pi(R^3 - r^3)
  • A plane cutting a sphere

    Circle of a cut

    ρ2+d2=R2\rho^2 + d^2 = R^2

Test yourself on Mensuration 3D

20 past CDS questions from this chapter, timed at 24 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.