PYQ Vault

CDS Mathematics · Quadratic Equations

Solving and Forming Quadratic Equations

A quadratic is fixed by the sum and the product of its roots, and when its coefficients add to zero one root is 1.

Why this matters

Fifteen PYQs. Two moves cover almost all of them: write the equation as x² − (sum)x + (product) = 0, and check whether the coefficients add to zero before doing any algebra. Irrational roots come in conjugate pairs, which answers the 'other root' questions at once.

Concept 1 of 2: Forming an equation from its roots

Expanding (x−α)(x−β)(x - \alpha)(x - \beta) gives x2−(α+β)x+αβx^2 - (\alpha + \beta)x + \alpha\beta. So the sum and the product are all you need to write the equation, and a change to the roots is a change to that sum and product.

Definition

  • The equation with roots α,β\alpha, \beta is x2−(α+β)x+αβ=0x^2 - (\alpha + \beta)x + \alpha\beta = 0, or any non-zero multiple of it.
  • For ax2+bx+c=0ax^2 + bx + c = 0: α+β=−ba\alpha + \beta = -\dfrac ba and αβ=ca\alpha\beta = \dfrac ca.
  • Copying errors: a wrong constant term leaves the SUM right; a wrong xx-coefficient leaves the PRODUCT right.
  • With rational coefficients, an irrational root p+qp + \sqrt q comes with its conjugate p−qp - \sqrt q.
  • To find an equation satisfied by a new quantity yy, express xx through yy and substitute.

Equation from sum and product

x2−(α+β)x+αβ=0x^2 - (\alpha + \beta)x + \alpha\beta = 0

Worked example

The roots of an equation have sum 55 and product 66. Form the equation whose roots are each one more.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2017 · CDS (I) 2017 — Elementary Mathematics · Q45Moderate

Example 1 · Quadratic Equations · Solving and Forming Quadratic Equations

Aman and Alok attempted to solve a quadratic equation. Aman made a mistake in writing down the constant term and ended up in roots (4,3)(4, 3). Alok made a mistake in writing down the coefficient of xx to get roots (3,2)(3, 2). The correct roots of the equation are

The sign of the sum

The xx-coefficient is MINUS the sum. Roots with sum 22 give x2−2x+…x^2 - 2x + \ldots, not x2+2x+…x^2 + 2x + \ldots, and the wrong-sign version is always among the options.

Concept 2 of 2: When the coefficients add to zero

Putting x=1x = 1 into ax2+bx+cax^2 + bx + c gives a+b+ca + b + c. If that is zero, 11 is a root, and the other root is the product ca\dfrac ca. Letter-heavy equations are built this way on purpose.

Definition

  • If a+b+c=0a + b + c = 0, the roots of ax2+bx+c=0ax^2 + bx + c = 0 are 11 and ca\dfrac ca.
  • If a−b+c=0a - b + c = 0, the roots are −1-1 and −ca-\dfrac ca.
  • If a root is given, substitute it to find an unknown coefficient, then use the sum or product for the other root.
  • Otherwise factorise, or use x=−b±b2−4ac2ax = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}.

Root 1

a+b+c=0  ⇒  x=1, caa + b + c = 0 \;\Rightarrow\; x = 1,\ \dfrac ca

Worked example

Find the roots of (p−q)x2+(q−r)x+(r−p)=0(p - q)x^2 + (q - r)x + (r - p) = 0.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2025 · CDS (II) 2025 — Elementary Mathematics · Q25Moderate

Example 2 · Quadratic Equations · Solving and Forming Quadratic Equations

If (a−b2)x2−(a+b2)x+b=0\left(\frac{a-b}{2}\right)x^2-\left(\frac{a+b}{2}\right)x+b=0, then what are the roots of this equation?

Clear the fractions first

The coefficient-sum test works on the equation as it stands, fractions and all, but the product ca\dfrac ca is easier to read after multiplying through. Do not multiply only some of the terms.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

Watch out for (2)

Test yourself on Quadratic Equations

20 past CDS questions from this chapter, timed at 24 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.