PYQ Vault

CDS Mathematics · Quadrilaterals

Trapeziums

In a trapezium the diagonals cut each other in the ratio of the parallel sides, and the line joining the midpoints of the legs is their average.

Why this matters

Eight PYQs, two of them HARD. Five use one pair of similar triangles — the two on the parallel sides, cut off by the diagonals — for ratios of lengths and, squared, of areas. The rest use the midline or an isosceles or right trapezium.

Concept 1 of 2: Diagonals and the four triangles

The parallel sides make alternate angles equal, so the triangles on them, AOBAOB and CODCOD, are similar in the ratio AB:CDAB : CD. The two side triangles have equal areas, because each is a big triangle on a parallel side minus the same piece.

Definition

  • AB∥CDAB \parallel CD: AOOC=BOOD=ABCD\dfrac{AO}{OC} = \dfrac{BO}{OD} = \dfrac{AB}{CD}.
  • [AOB]:[COD]=AB2:CD2[AOB] : [COD] = AB^2 : CD^2.
  • The side triangles are equal: [AOD]=[BOC][AOD] = [BOC], and [AOD]2=[AOB]⋅[COD][AOD]^2 = [AOB]\cdot[COD].
  • A line parallel to the parallel sides cuts the legs in the same ratio.

Diagonal ratio

AOOC=BOOD=ABCD\dfrac{AO}{OC} = \dfrac{BO}{OD} = \dfrac{AB}{CD}

Worked example

In trapezium ABCDABCD, AB∥CDAB \parallel CD and 3AB=5CD3AB = 5CD. Find [AOB]:[COD][AOB] : [COD].
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2021 · CDS (I) 2021 — Elementary Mathematics · Q89Moderate

Example 1 · Quadrilaterals · Trapeziums

ABCDABCD is a trapezium in which ABAB is parallel to DCDC and 2AB=3DC2AB = 3DC. The diagonals ACAC and BDBD intersect at OO. What is the ratio of the area of △AOB\triangle AOB to that of △DOC\triangle DOC?

Lengths go straight, areas go squared

The diagonals cut each other in the ratio AB:CDAB : CD. The AREAS of the triangles on the parallel sides go as its square. Using one where the other is asked is the standard wrong option.

Which sides are parallel?

Some items make AD∥BCAD \parallel BC instead of AB∥CDAB \parallel CD. The similar triangles are then AODAOD and COBCOB; relabel before using the rules.

Concept 2 of 2: The midline and special trapeziums

The segment joining the midpoints of the legs runs halfway up the trapezium, so its length is halfway between the two parallel sides: their average.

Definition

  • Midline =a+b2= \dfrac{a + b}{2}, where a,ba, b are the parallel sides. Area == midline ×\times height.
  • Isosceles trapezium (equal legs, not a parallelogram): base angles equal, and it is always cyclic.
  • A trapezium with an incircle: the height is the circle's diameter, and each leg equals the sum of the two tangents from its ends.

Midline

EF=AB+CD2EF = \dfrac{AB + CD}{2}

Worked example

A trapezium's midline is 1313 cm and its parallel sides differ by 66 cm. Find the parallel sides.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2022 · CDS (I) 2022 — Elementary Mathematics · Q73Moderate

Example 2 · Quadrilaterals · Trapeziums

ABCDABCD is a trapezium in which ABAB is parallel to DCDC. Let EE and FF be the midpoints on ADAD and BCBC respectively. If EF=10EF = 10 cm and AB−DC=4AB - DC = 4 cm, then what is the value of AB×DCAB \times DC?

Equal legs do not make it a trapezium

With one pair of sides parallel and the other pair equal, the figure may still be a parallelogram. Only when the equal sides are NOT parallel is it an isosceles trapezium, and so cyclic.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

Watch out for (3)

Test yourself on Quadrilaterals

15 past CDS questions from this chapter, timed at 18 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.