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CDS Physics · Work, Energy and Power

Work, Energy and Power

When a force does work and when it does none, kinetic and potential energy and how they trade places, and power as work done per second.

Why this matters

Five CDS questions from 2020 (II) to 2025 (II), three of them in the two 2025 papers. Two are short power sums, and the other three each test one idea: zero work, energy and momentum, and potential energy in a pendulum.

Concept 1 of 3: Work done by a force

In physics, work is done only when a force moves something along the direction of the force. Push a box across the floor and you do work. Hold a heavy bag still and you get tired, but you do no work on the bag, because it does not move. A force at right angles to the motion also does no work: it can turn the motion, but it cannot speed it up or slow it down.

Definition

Work and its sign:

  • W=Fscos⁡θW = Fs\cos\theta, where θ\theta is the angle between the force and the displacement. Unit: the joule (1 J = 1 N m).
  • Positive work: force along the motion (θ<90°\theta < 90°), the body speeds up.
  • Zero work: force perpendicular to the motion (θ=90°\theta = 90°), or no displacement at all.
  • Negative work: force against the motion (θ>90°\theta > 90°), as friction does.
  • In circular motion the string's pull points to the centre, at right angles to the motion all the way round, so it does no work.

Work done by a constant force

W=Fscos⁡θW = Fs\cos\theta
  • Fsize of the force
  • ssize of the displacement
  • θangle between the force and the displacement

Worked example

A rope pulls a box 10 m along level ground. The pull is 50 N, at 60° to the ground. How much work does the rope do?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2025 · CDS (II) 2025 — General Knowledge · Q24Easy

Example 1 · Work, Energy and Power · Work, Energy and Power

When a stone tied to a string is whirled in a circle, the work done on it by the string :

Effort is not work

Work needs a displacement along the force. Holding a load still, or carrying it on a level path, does no work against gravity, however tiring it feels.

A centre-pointing force does no work

The pull of a string on a whirled stone, and the gravity on a body moving in a circle about it, point to the centre, at 90° to the motion. The work done is zero, not positive and not dependent on the mass.

Concept 2 of 3: Kinetic and potential energy

Kinetic energy is the energy a body has because it is moving; potential energy is the energy it has because of its height. A swinging pendulum keeps trading one for the other: at the ends of the swing it stops for an instant and all its energy is potential, at the lowest point it moves fastest and its potential energy is least. Because kinetic energy depends on the square of the speed, doubling the speed makes it four times as large.

Definition

The two forms and how they link:

  • Kinetic energy K=12mv2K = \tfrac{1}{2}mv^{2}. In terms of momentum p=mvp = mv: K=p22mK = \dfrac{p^{2}}{2m}, and p=2mKp = \sqrt{2mK}.
  • So at fixed mass, KK goes as v2v^{2} and as p2p^{2}.
  • Potential energy near the ground U=mghU = mgh: it depends on the height above the chosen level.
  • Conservation: with no friction, K+UK + U stays constant. A body falling from height hh reaches v=2ghv = \sqrt{2gh}.
  • Pendulum: potential energy is least at the mean (lowest) position and greatest at the two ends; kinetic energy is the other way round.
  • Work-energy theorem: the net work done on a body equals its change in kinetic energy.

Kinetic and potential energy

K=12mv2=p22mU=mghK+U=constantv=2ghK = \tfrac{1}{2}mv^{2} = \dfrac{p^{2}}{2m} \qquad U = mgh \qquad K + U = \text{constant} \qquad v = \sqrt{2gh}
  • Kkinetic energy
  • Upotential energy
  • pmomentum
  • hheight above the reference level

Worked example

A 2 kg ball moves at 3 m/s. Find its kinetic energy. What does the kinetic energy become if the speed is tripled?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2020 · CDS (II) 2020 — General Knowledge · Q86Moderate

Example 2 · Work, Energy and Power · Work, Energy and Power

If the linear momentum of a moving object gets doubled due to application of a force, then its kinetic energy will

Kinetic energy follows the square

Doubling the speed or the momentum (at the same mass) makes the kinetic energy four times, not two times. Halving them makes it one quarter.

Lowest point, least potential energy

A pendulum bob has the least potential energy at its mean position, the lowest point, and the most at the two extreme positions where it is highest. Its kinetic energy is the opposite.

Concept 3 of 3: Power

Power is how fast work gets done. Two people can lift the same load up the same stairs, but the one who does it in less time has more power. The least work needed to lift a load is the potential energy it gains, so the least power is that energy divided by the time taken.

Definition

Power and its units:

  • P=WtP = \dfrac{W}{t}. Unit: the watt (1 W = 1 J/s); 1 kW = 1000 W; 1 horsepower is about 746 W.
  • Lifting: the least power to raise mass mm through height hh in time tt is P=mghtP = \dfrac{mgh}{t}.
  • At the same work, power and time are inversely related: half the time means twice the power.
  • The kilowatt hour (kWh) is a unit of energy, not power: 1 kWh = 3.6×1063.6 \times 10^{6} J.
  • If the time is given in minutes, either convert it to seconds or keep the answer in joules per minute: compare like with like.

Power

P=WtPlift=mght1 kWh=3.6×106 JP = \dfrac{W}{t} \qquad P_{\text{lift}} = \dfrac{mgh}{t} \qquad 1\ \text{kWh} = 3.6 \times 10^{6}\ \text{J}
  • Ppower
  • Wwork done
  • ttime taken

Worked example

A pump lifts 200 kg of water to a tank 15 m high in one minute. What is the least power it must deliver? (Take g=10g = 10 m/s².)
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2025 · CDS (I) 2025 — General Knowledge · Q24Easy

Example 3 · Work, Energy and Power · Work, Energy and Power

The minimum power required to lift a mass of 50 kg up to a vertical distance of 8 m in 10 s is : (Take g=10 m/s2g = 10\ \text{m/s}^2)

kW is power, kWh is energy

The kilowatt measures power; the kilowatt hour measures energy (power × time). An electricity bill counts kWh, the energy used.

Least power uses the potential energy gained

To lift a load at the least power, the work is just mghmgh. Do not add the kinetic energy unless the question says the load ends up moving.
Drill 1 more on power

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • Work done by a force

    Work done by a constant force

    W=Fscos⁡θW = Fs\cos\theta
  • Kinetic and potential energy

    Kinetic and potential energy

    K=12mv2=p22mU=mghK+U=constantv=2ghK = \tfrac{1}{2}mv^{2} = \dfrac{p^{2}}{2m} \qquad U = mgh \qquad K + U = \text{constant} \qquad v = \sqrt{2gh}
  • Power

    Power

    P=WtPlift=mght1 kWh=3.6×106 JP = \dfrac{W}{t} \qquad P_{\text{lift}} = \dfrac{mgh}{t} \qquad 1\ \text{kWh} = 3.6 \times 10^{6}\ \text{J}

Watch out for (6)

Test yourself on a real paper

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