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IMAT Mathematics · Numbers, Powers and Logarithms

Scientific Notation and Logarithms

Scientific notation keeps very large and very small numbers under control; a logarithm is the exponent that turns its base into a given number, and its laws turn products into sums.

Why this matters

Calculations in scientific notation appeared in 2014, 2016, 2018 and 2022, and logarithms in 2012, 2013, 2015, 2017 and 2026. The 2026 question needed only the definition of log₁₀; the older ones used the laws to simplify or rearrange.

Concept 1 of 4: Scientific notation and orders of magnitude

Writing a number as a value between 1 and 10 times a power of ten splits it into two parts you can handle separately: the digits and the size. Multiply the digit parts, add the powers of ten, then tidy up so the digit part is back between 1 and 10.

Definition

A number is in scientific notation when written a×10na \times 10^n with 1≤a<101 \le a < 10 and nn an integer.

  • Multiply: multiply the aa parts and add the exponents. Divide: divide and subtract.
  • Renormalise at the end: 30×10−3=3.0×10−230 \times 10^{-3} = 3.0 \times 10^{-2} (the exponent goes up by one when aa is divided by 10).
  • Square root: first make the exponent even. 4.9×105=49×104=7×102\sqrt{4.9 \times 10^5} = \sqrt{49 \times 10^4} = 7 \times 10^2.
  • The order of magnitude is the power of ten that sets the size: 3.2×1063.2 \times 10^6 is of order 10610^6.

Scientific notation

x=a×10n,1≤a<10,n∈Zx = a \times 10^{n}, \qquad 1 \le a < 10, \quad n \in \mathbb{Z}
  • aathe digit part (mantissa)
  • nnthe power of ten, a whole number

Worked example

Evaluate (6×104)×(5×10−7)2.5×10−3\dfrac{(6 \times 10^{4}) \times (5 \times 10^{-7})}{\sqrt{2.5 \times 10^{-3}}} in scientific notation.
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15 × 10⁴ is not in scientific notation

The digit part must be at least 1 and less than 10. 15×104=1.5×10515 \times 10^4 = 1.5 \times 10^5: moving the decimal point one place left raises the exponent by one. Forgetting this gives an option that is ten times too small or too large.

Concept 2 of 4: Logarithm: definition, log₁₀ and ln

A logarithm answers one question: what power do I raise the base to, to get this number? log⁡28=3\log_2 8 = 3 because 23=82^3 = 8. A logarithm is an exponent, so every fact about logs comes from a fact about powers.

Definition

For a base b>0b > 0, b≠1b \ne 1, and a number x>0x > 0: log⁡bx\log_b x is the exponent yy with by=xb^y = x.

  • log⁡b1=0\log_b 1 = 0, log⁡bb=1\log_b b = 1, log⁡b(bk)=k\log_b (b^k) = k and blog⁡bx=xb^{\log_b x} = x.
  • log⁡x\log x or log⁡10x\log_{10} x is the common logarithm (base 10): log⁡1000=3\log 1000 = 3, log⁡0.01=−2\log 0.01 = -2.
  • ln⁡x\ln x is the natural logarithm, base e≈2.718e \approx 2.718: ln⁡e=1\ln e = 1, ln⁡1=0\ln 1 = 0.
  • The logarithm of zero or of a negative number is not defined. A negative logarithm only means 0<x<10 < x < 1.

Definition of the logarithm

log⁡bx=ymeansby=x\log_b x = y \quad\text{means}\quad b^{y} = x
  • bbthe base, positive and not 1
  • xxthe argument, positive

Worked example

Evaluate (a) log⁡232\log_2 32, (b) log⁡100.001\log_{10} 0.001, (c) ln⁡e4\ln e^4, and (d) solve log⁡3x=4\log_3 x = 4.
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A negative logarithm is fine; a negative argument is not

log⁡0.01=−2\log 0.01 = -2 is perfectly good: the number is between 0 and 1. But log⁡(−2)\log(-2) and log⁡0\log 0 do not exist, because no power of a positive base is zero or negative.

Concept 3 of 4: Laws of logarithms and change of base

Logarithms are exponents, and exponents add when numbers multiply. So the log of a product is the sum of the logs, the log of a quotient is the difference, and the log of a power brings the power down in front.

Definition

For positive x,yx, y and any valid base:

  • Product: log⁡(xy)=log⁡x+log⁡y\log(xy) = \log x + \log y.
  • Quotient: log⁡xy=log⁡x−log⁡y\log \frac{x}{y} = \log x - \log y.
  • Power: log⁡xk=klog⁡x\log x^k = k \log x (also for roots: log⁡x=12log⁡x\log \sqrt{x} = \frac{1}{2}\log x).
  • Change of base: log⁡bx=log⁡xlog⁡b\log_b x = \frac{\log x}{\log b}, using any common base (10, ee or 2).
  • There is no law for log⁡(x+y)\log(x + y).

Laws of logarithms

log⁡(xy)=log⁡x+log⁡ylog⁡xy=log⁡x−log⁡ylog⁡xk=klog⁡xlog⁡bx=log⁡xlog⁡b\log(xy) = \log x + \log y \qquad \log\frac{x}{y} = \log x - \log y \qquad \log x^{k} = k\log x \qquad \log_b x = \frac{\log x}{\log b}

Worked example

(a) Write log⁡x3100 y2\log \dfrac{x^3}{100\,y^2} in terms of log⁡x\log x and log⁡y\log y (base 10). (b) Given log⁡2=a\log 2 = a and log⁡3=b\log 3 = b, write log⁡45\log 45 in terms of aa and bb. (c) Evaluate log⁡832\log_8 32.
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The log of a sum does not split

log⁡(x+y)\log(x + y) is not log⁡x+log⁡y\log x + \log y; that sum equals log⁡(xy)\log(xy). Likewise log⁡xlog⁡y\frac{\log x}{\log y} is not log⁡xy\log \frac{x}{y}: the first is a change of base, the second a difference of logs.

Concept 4 of 4: Solving exponential equations and rearranging log relations

When the unknown is in the exponent, either write both sides as powers of one base and match the exponents, or take logarithms to bring the exponent down. A relation between logs undoes into a relation between powers: a sum of logs becomes a product, and a number added on becomes a factor.

Definition

  • Common base: if both sides are powers of the same base, set the exponents equal.
  • Take logs: ax=ca^x = c gives x=log⁡clog⁡ax = \frac{\log c}{\log a} for c>0c > 0.
  • axa^x is always positive, so ax=ca^x = c with c≤0c \le 0 has no solution.
  • Undoing a log relation: log⁡y=klog⁡x+c\log y = k \log x + c means y=10c xky = 10^c\, x^k; with ln⁡\ln it means y=ecxky = e^c x^k.
  • Harder equations (a substitution, or a logarithm of an expression in xx) are in Equations and Inequalities.

Exponential equation by logs

ax=c  ⇒  x=log⁡clog⁡a(c>0)a^{x} = c \;\Rightarrow\; x = \frac{\log c}{\log a} \qquad (c > 0)

Worked example

(a) Solve 32x−1=273^{2x - 1} = 27. (b) Solve 5x=405^x = 40. (c) Given log⁡y=3log⁡x−2\log y = 3\log x - 2 (base 10), write yy in terms of xx.
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The constant in a log relation becomes a factor

log⁡y=2log⁡x+1\log y = 2\log x + 1 gives y=10x2y = 10x^2, not y=x2+1y = x^2 + 1. The 1 is log⁡10\log 10, and logs that add come from numbers that multiply.

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