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JEE Mains Maths · Complex Numbers

Lines and Circles in the Complex Plane

Reading an equation in z as a straight line or a circle: equal distances from two points, linear equations in z and its conjugate, and circles given by a centre or by a ratio of distances.

Why this matters

Seventeen PYQs, twelve of them multiple choice. Seven are straight lines — perpendicular bisectors and linear equations in z and its conjugate; ten are circles, often a ratio of two distances. Most then intersect the line or circle with another curve. Two ideas cover the page.

Concept 1 of 2: Straight lines

∣z−a∣=∣z−b∣|z-a|=|z-b| says zz is equally far from aa and bb: the perpendicular bisector of the segment abab. A linear equation aˉz+azˉ+c=0\bar az+a\bar z+c=0 with cc real is a line, because aˉz+azˉ=2 Re(aˉz)\bar az+a\bar z=2\,\mathrm{Re}(\bar az) is linear in xx and yy. So is ∣z−a∣2−∣z−b∣2=k|z-a|^2-|z-b|^2=k, since the x2+y2x^2+y^2 terms cancel. To meet a circle, substitute the line into it.

Definition

  • ∣z−a∣=∣z−b∣|z-a|=|z-b|: the perpendicular bisector of aa and bb.
  • aˉz+azˉ+c=0\bar az+a\bar z+c=0, cc real: a line.
  • z(p+iq)+zˉ(p−iq)=2(px−qy)z(p+iq)+\bar z(p-iq)=2(px-qy).
  • ∣z−a∣2−∣z−b∣2=k|z-a|^2-|z-b|^2=k: a line at right angles to abab.

Line in complex form

aˉz+azˉ+c=0(c∈R)\bar az+a\bar z+c=0\quad(c\in\mathbb R)

Worked example

Write ∣z−1∣=∣z+3i∣|z-1|=|z+3i| in xx and yy.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 25 Jan 2023 · Q65Moderate

Example 1 · Complex Numbers · Lines and Circles in the Complex Plane

Let z1=2+3iz_{1}= 2 + 3i and z2=3+4iz_{2}= 3 + 4i. The set S={z∈C:∣z−z1∣2−∣z−z2∣2=∣z1−z2∣2}S =\left\{ z \in C:\left| z -z_{1} \right|^{2}-\left| z -z_{2} \right|^{2}=\left| z_{1}-z_{2} \right|^{2} \right\} represents a

Expand before trusting a sign

z(1+i)+zˉ(1−i)=2(x−y)z(1+i)+\bar z(1-i)=2(x-y), while z(1−i)+zˉ(1+i)=2(x+y)z(1-i)+\bar z(1+i)=2(x+y). Expanding once with z=x+iyz=x+iy avoids picking the wrong half-plane or line.

Concept 2 of 2: Circles

∣z−a∣=r|z-a|=r is the circle with centre aa and radius rr. A ratio of distances, ∣z−a∣=k∣z−b∣|z-a|=k|z-b| with k≠1k\neq1, is also a circle: square, expand, and divide by the coefficient of x2+y2x^2+y^2 before reading off the centre. In complex form, zzˉ+αˉz+αzˉ+d=0z\bar z+\bar\alpha z+\alpha\bar z+d=0 is the circle with centre −α-\alpha and radius ∣α∣2−d\sqrt{|\alpha|^2-d}.

Definition

  • ∣z−a∣=r|z-a|=r: centre aa, radius rr.
  • ∣z−a∣=k∣z−b∣|z-a|=k|z-b|, k≠1k\neq1: a circle (for k=1k=1, a line).
  • zzˉ+αˉz+αzˉ+d=0z\bar z+\bar\alpha z+\alpha\bar z+d=0: centre −α-\alpha, r2=∣α∣2−dr^2=|\alpha|^2-d.
  • ∣z−α∣2+∣z−β∣2=2∣z−m∣2+12∣α−β∣2|z-\alpha|^2+|z-\beta|^2=2|z-m|^2+\frac12|\alpha-\beta|^2, m=α+β2m=\frac{\alpha+\beta}2.

Circle in complex form

zzˉ+αˉz+αzˉ+d=0: centre −α, r=∣α∣2−dz\bar z+\bar\alpha z+\alpha\bar z+d=0:\ \text{centre }-\alpha,\ r=\sqrt{|\alpha|^2-d}

Worked example

Find the centre and radius of ∣z+2∣=3∣z−2∣|z+2|=3|z-2|.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 1 February 2023 · Q78Moderate

Example 2 · Complex Numbers · Lines and Circles in the Complex Plane

If the center and radius of the circle ∣z−2z−3∣=2\left| \frac{z - 2}{z - 3} \right|= 2 are respectively (α,β)(\alpha,\beta) and γ\gamma. then 3(α+β+γ)3(\alpha + \beta + \gamma) is equal to

Divide before reading the centre

After squaring a ratio of distances the x2+y2x^2+y^2 term has a coefficient like 3 or 8. Divide through by it first; reading the centre from the undivided equation gives the wrong point.
Drill 9 more on circles

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

  • Straight lines

    Line in complex form

    aˉz+azˉ+c=0(c∈R)\bar az+a\bar z+c=0\quad(c\in\mathbb R)
  • Circles

    Circle in complex form

    zzˉ+αˉz+αzˉ+d=0: centre −α, r=∣α∣2−dz\bar z+\bar\alpha z+\alpha\bar z+d=0:\ \text{centre }-\alpha,\ r=\sqrt{|\alpha|^2-d}

Watch out for (2)

Test yourself on Complex Numbers

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.