PYQ Vault

JEE Mains Maths · Differential Equations

Using a Linear Solution

Questions where solving the linear equation is only the first half: the constant is fixed by a limit instead of a point, or the solution is then maximised, differentiated, integrated or compared with another solution.

Why this matters

Twenty-two PYQs, eight of them numerical answer, and 2022 alone has nine. The equation is routine; the marks are in what comes after. Seven fix the constant from behaviour at infinity or compare two solutions, eight need a maximum or a derivative of the solution, and seven integrate it. Three ideas cover the page.

Concept 1 of 3: Limits that fix the constant

The general solution of y′+ky=Qy'+ky=Q is a particular part plus Ce−kxCe^{-kx}. If the question says the limit at +∞+\infty or −∞-\infty is finite, the exponential part must vanish there or be killed: either C=0C=0, or the exponent's sign is forced. Two solutions of the same linear equation differ by Ce−∫PCe^{-\int P}, which is never zero unless C=0C=0, so distinct solutions never cross.

Definition

  • y=yp+Ce−∫P dxy=y_p+Ce^{-\int P\,dx}.
  • lim⁡x→∞y\lim_{x\to\infty}y finite and exe^{x} in the solution: C=0C=0.
  • f′=αf+βf'=\alpha f+\beta: f=Ceαx−βαf=Ce^{\alpha x}-\frac\beta\alpha; a finite limit as x→−∞x\to-\infty needs α>0\alpha>0 and equals −βα-\frac\beta\alpha.
  • Two distinct solutions of a linear equation never intersect.

General solution with constant coefficient

y′+ky=Q ⇒ y=yp(x)+Ce−kxy'+ky=Q\ \Rightarrow\ y=y_p(x)+Ce^{-kx}

Worked example

f′(x)=2f(x)−4f'(x)=2f(x)-4 and lim⁡x→−∞f(x)\lim_{x\to-\infty}f(x) is finite, with f(0)=3f(0)=3. Find f(ln⁡2)f(\ln2).
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2024 · 1 February 2024 · Q157Moderate

Example 1 · Differential Equations · Using a Linear Solution

Let α\alpha be a non-zero real number. Suppose f:R→f:R \rightarrow RR is a differentiable function such that f(0)=2f(0) = 2 and lim⁡x→−∞f(x)=1\lim_{x \rightarrow - \infty} f(x) = 1. If f′(x)=αf(x)+3f^{'}(x) = \alpha f(x) + 3, for all x∈Rx \in R, then f(−log⁡e2)f\left( -\log_{e}2 \right) is equal to

Which infinity

eαx→0e^{\alpha x}\to0 as x→−∞x\to-\infty only when α>0\alpha>0. Read which end the limit is taken at before deciding which sign of α\alpha the condition forces.

Concept 2 of 3: Maxima, critical points and derivatives of the solution

For an extremum, you rarely need the solution's formula differentiated from scratch: the equation itself gives y′y'. Set y′=0y'=0 using the equation, or write the solution in a simple variable such as t=cos⁡xt=\cos x and maximise the quadratic. For a combination like xy′′+2y′xy''+2y', notice it is (xy)′′(xy)''.

Definition

  • Critical point: y′=0y'=0, read from the equation.
  • y=cos⁡x−2cos⁡2xy=\cos x-2\cos^2x: a quadratic in t=cos⁡xt=\cos x, maximum at t=14t=\frac14.
  • (xy)′=xy′+y(xy)'=xy'+y, (xy)′′=xy′′+2y′(xy)''=xy''+2y'.
  • z=x2y−exz=x^2y-e^x with xy′+2y=xexxy'+2y=xe^x: z′=x(xy′+2y)−exz'=x(xy'+2y)-e^x.

Derivative from the equation

dydx=Q(x)−P(x) y  (no need to differentiate the solution)\frac{dy}{dx}=Q(x)-P(x)\,y\ \ \text{(no need to differentiate the solution)}

Worked example

y′+ytan⁡x=sin⁡xy'+y\tan x=\sin x with y(0)=0y(0)=0. Find the maximum of yy on (0,π2)\left(0,\frac\pi2\right).
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2022 · 26 July 2022 · Q71Moderate

Example 2 · Differential Equations · Using a Linear Solution

If dydx+2ytanx=sin⁡x,0<x<π2\frac{dy}{dx}+ 2ytanx = \sin x,0 < x <\frac{\pi}{2} and y(π3)=y\left( \frac{\pi}{3} \right)=0, then the maximum value of y(x)y(x) is

Check the endpoint and the domain

A quadratic in t=cos⁡xt=\cos x has its vertex inside the range only if that value of tt is attainable on the given interval. Otherwise the extreme value is at an end.

Concept 3 of 3: Integrating the solution: odd parts and areas

Many questions ask for ∫−aay dx\int_{-a}^{a}y\,dx after solving. Split the solution into odd and even parts: the odd part integrates to zero on a symmetric interval, so only the even part needs work. For an area between the solution and a line, find where they meet and integrate the difference.

Definition

  • ∫−aag=0\int_{-a}^{a}g=0 for odd gg; =2∫0ag=2\int_0^ag for even gg.
  • Typical: y1−x2=x55+x2y\sqrt{1-x^2}=\frac{x^5}{5}+x^2: the x5x^5 term is odd.
  • ∫x21−x2dx\int\frac{x^2}{\sqrt{1-x^2}}dx: put x=sin⁡θx=\sin\theta.
  • Area between y=fy=f and a line: ∫∣f−line∣\int|f-\text{line}| between the meeting points.

Symmetric interval

∫−aa(godd+geven) dx=2∫0ageven dx\int_{-a}^{a}\big(g_{\text{odd}}+g_{\text{even}}\big)\,dx=2\int_0^{a}g_{\text{even}}\,dx

Worked example

y=x3+x2cos⁡xy=x^3+x^2\cos x solves an equation. Find ∫−11y dx\int_{-1}^{1}y\,dx.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2022 · 26 July 2022 · Q160Moderate

Example 3 · Differential Equations · Using a Linear Solution

Let the solution curve y=f(x)y = f(x) of the differential equation dydx+xyx2−1=x4+2x1−x2,x∈(−1,1)\frac{dy}{dx}+\frac{xy}{x^{2}- 1}=\frac{x^{4}+ 2x}{\sqrt{1 -x^{2}}},x \in ( - 1,1) pass through the origin. Then ∫−3232f(x)dx\int_{-\frac{\sqrt{3}}{2}}^{\frac{\sqrt{3}}{2}} f(x)dx is equal to

Split before integrating

Integrating the whole solution term by term on [−a,a][-a,a] wastes time on parts that cancel. Identify the odd terms first and drop them.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • Limits that fix the constant

    General solution with constant coefficient

    y′+ky=Q ⇒ y=yp(x)+Ce−kxy'+ky=Q\ \Rightarrow\ y=y_p(x)+Ce^{-kx}
  • Maxima, critical points and derivatives of the solution

    Derivative from the equation

    dydx=Q(x)−P(x) y  (no need to differentiate the solution)\frac{dy}{dx}=Q(x)-P(x)\,y\ \ \text{(no need to differentiate the solution)}
  • Integrating the solution: odd parts and areas

    Symmetric interval

    ∫−aa(godd+geven) dx=2∫0ageven dx\int_{-a}^{a}\big(g_{\text{odd}}+g_{\text{even}}\big)\,dx=2\int_0^{a}g_{\text{even}}\,dx

Watch out for (3)

Test yourself on Differential Equations

20 past JEE Mains questions from this chapter, timed at 48 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.