MHT-CET Chemistry · Alkanes
Free-Radical Halogenation: Reactivity and Selectivity
In UV light a halogen substitutes an H on an alkane through free radicals; fluorine reacts most violently and iodine least, and bromine is so selective that it almost always replaces the H on the most substituted carbon.
Why this matters
4 PYQs, all EASY: one reactivity order and three 'major product of bromination' questions. One card.
Concept 1 of 1: Halogen Reactivity and Bromine's Selectivity
Definition
- Reactivity: F₂ > Cl₂ > Br₂ > I₂. Iodination is reversible and needs an oxidant.
- Radical stability: 3° > 2° > 1° > CH₃•.
- Bromination (hν): isobutane (CH₃)₃CH → (CH₃)₃CBr, 2-bromo-2-methylpropane, ~99%. Propane → 2-bromopropane.
Practice this conceptself-check
The same idea in a real exam question:
Example 1 · Alkanes · Reactions of Alkanes, Free Radical Halogenation
Counting hydrogens instead of ranking them
Summary — formulas & gotchas at a glance
A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.
Reference tables (1)
Watch out for (1)
- Counting hydrogens instead of ranking them→ Halogen Reactivity and Bromine's Selectivity
Test yourself on Alkanes
15 past MHT-CET questions from this chapter, timed at 14 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.