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MHT-CET Chemistry · Aromatic Compounds

Electrophilic Substitution: the Reactions and Where the Group Goes

Benzene keeps its aromatic ring by substituting rather than adding: an electrophile (Cl⁺, NO₂⁺, R⁺, RCO⁺, HCO⁺) replaces a ring H, and a group already on the ring decides whether the new one goes ortho/para or meta.

Why this matters

12 PYQs, none HARD. Seven are about direction — which group is ortho/para directing, which starting compound gives a stated o/p pair, how much para product forms; five are about the reactions and their reagents — Gattermann–Koch, iodination, hexachlorobenzene. Two cards.

Concept 1 of 2: The Substitution Reactions and Their Reagents

Every reaction here is the same three steps: make an electrophile with a Lewis acid, let it attack the ring to form a σ-complex, lose H⁺ to get the ring back. So the thing to learn for each is the reagent pair that makes the electrophile.

Definition

  • Halogenation: X₂ / FeX₃ or anhydrous AlCl₃. Excess Cl₂ gives hexachlorobenzene, C₆Cl₆.
  • Iodination is reversible — the HI formed reduces iodobenzene back — so it is not done directly.
  • Nitration: conc. HNO₃ + conc. H₂SO₄ (NO₂⁺).
  • Friedel–Crafts: RCl or RCOCl with anhydrous AlCl₃.
  • Gattermann–Koch: CO + HCl, anhydrous AlCl₃, pressure → benzaldehyde.
ReactionReagentProduct from benzene
Gattermann–Koch formylationCO, HCl / anhyd. AlCl₃C₆H₅CHOQ
Exhaustive chlorinationExcess Cl₂ / AlCl₃C₆Cl₆Q
IodinationI₂Not possible — reversibleQ
Friedel–Crafts alkylationCH₃Cl / anhyd. AlCl₃Toluene
Nitrationconc. HNO₃ + conc. H₂SO₄Nitrobenzene
Practice this conceptself-check · 2 quick reps

The same idea in a real exam question:

MHT-CET · 2023 · 10th May Shift 1 · Q81Moderate

Example 1 · Aromatic Compounds · Electrophilic Aromatic Substitution

Identify the product obtained in following reaction: C6H6→CO, HCl/Anhyd. AlCl3, pressure\text{C}_6\text{H}_6 \xrightarrow{\text{CO, HCl/Anhyd. AlCl}_3\text{, pressure}} product

Hexachlorobenzene as C₆H₆Cl₆

C₆H₆Cl₆ is benzene hexachloride (BHC), made by ADDITION of Cl₂ in UV light. Hexachlorobenzene is SUBSTITUTION of all six H: C₆Cl₆.

Concept 2 of 2: Directing Effects: Ortho/Para or Meta

A group that pushes electrons into the ring (–OH, –OCH₃, –NH₂, –CH₃, and the halogens through their lone pairs) makes the ortho and para positions richest, so the new group goes there — with para usually the major product because it is less crowded. A group that pulls electrons out (–NO₂, –CHO, –COOH, –CN) leaves meta the least deactivated.

Definition

  • o/p directors: –OH, –OCH₃, –NH₂, –R, –X (halogens deactivate but still direct o/p).
  • m directors: –NO₂, –CHO, –COOH, –COR, –CN, –SO₃H.
  • Para is the major product: chlorobenzene + Cl₂ → 1,4-dichlorobenzene; anisole + Br₂/AcOH → p-bromoanisole ~90%.
  • Working backwards: 2- and 4-substituted products from CH₃Cl or CH₃COCl → the start was chlorobenzene.
  • Phenol + conc. HNO₃/H₂SO₄ → 2,4,6-trinitrophenol (picric acid) — –OH activates all three positions.
StartReagentMajor product
ChlorobenzeneCl₂ / AlCl₃1,4-dichlorobenzeneQ
AnisoleBr₂ in acetic acidp-bromoanisole (90%)Q
ChlorobenzeneCH₃Cl / anhyd. AlCl₃2- and 4-chlorotolueneQ
ChlorobenzeneCH₃COCl / anhyd. AlCl₃2- and 4-chloroacetophenoneQ
Phenolconc. HNO₃ / conc. H₂SO₄2,4,6-trinitrophenolQ
Practice this conceptself-check · 2 quick reps

The same idea in a real exam question:

MHT-CET · 2024 · 11th May Shift 2 · Q70Easy

Example 2 · Aromatic Compounds · Electrophilic Aromatic Substitution

Identify the ortho/para directing group in EAS reaction from following.

Toluene as the starting compound

Toluene with CH₃Cl gives xylenes, and with anything it cannot give a CHLORO product. The chlorine in both products must have been on the ring already — the start is chlorobenzene.

Mononitration of phenol

Dilute HNO₃ gives o- and p-nitrophenol. With CONCENTRATED HNO₃ and H₂SO₄ all three activated positions are nitrated.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Reference tables (2)

The Substitution Reactions and Their Reagents5 rows
ReactionReagentProduct from benzene
Gattermann–Koch formylationCO, HCl / anhyd. AlCl₃C₆H₅CHOQ
Exhaustive chlorinationExcess Cl₂ / AlCl₃C₆Cl₆Q
IodinationI₂Not possible — reversibleQ
Friedel–Crafts alkylationCH₃Cl / anhyd. AlCl₃Toluene
Nitrationconc. HNO₃ + conc. H₂SO₄Nitrobenzene
Directing Effects: Ortho/Para or Meta5 rows
StartReagentMajor product
ChlorobenzeneCl₂ / AlCl₃1,4-dichlorobenzeneQ
AnisoleBr₂ in acetic acidp-bromoanisole (90%)Q
ChlorobenzeneCH₃Cl / anhyd. AlCl₃2- and 4-chlorotolueneQ
ChlorobenzeneCH₃COCl / anhyd. AlCl₃2- and 4-chloroacetophenoneQ
Phenolconc. HNO₃ / conc. H₂SO₄2,4,6-trinitrophenolQ

Watch out for (3)

Test yourself on Aromatic Compounds

15 past MHT-CET questions from this chapter, timed at 14 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.