NDA Maths · Matrices & Determinants

Special Determinants: Trig, Complex, ω, Polynomial

Determinants whose entries are trig functions, complex numbers, cube roots of unity, or polynomial/sequence terms — each family has an identity that collapses it, very often to 0.

Why this matters

Twenty PYQs and the joint-hardest area in the chapter (50% HARD). These look intimidating but reward pattern recognition: a trig identity, ω's relation 1 + ω + ω² = 0, the powers of i, or an AP/GP row that forces two rows to be dependent. The four families below cover them — and the answer is 0 far more often than you'd expect.

Test yourself — a quick 14-question Matrices & Determinants recall quiz, instant score.

Concept 1 of 4

Trigonometric determinants

Intuition

When entries are trig functions, the move is to apply an identity (Pythagorean, sum-to-product, or a triangle relation A+B+C=πA+B+C = \pi) so that two rows/columns become equal or proportional — and the determinant drops to 0.

Definition

Use sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1, double-angle, and (for triangle problems) A+B+C=πA + B + C = \pi. Many such determinants are identically 0 because a trig identity makes rows dependent. Expand only after simplifying with the identity.

Worked example

Evaluate sinθcosθcosθsinθ\begin{vmatrix}\sin\theta & \cos\theta\\ -\cos\theta & \sin\theta\end{vmatrix}.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 1Matrices & DeterminantsEASY
The value of the determinant cos2θ2sin2θ2sin2θ2cos2θ2\begin{vmatrix}\cos^2\dfrac{\theta}{2} & \sin^2\dfrac{\theta}{2} \\ \sin^2\dfrac{\theta}{2} & \cos^2\dfrac{\theta}{2}\end{vmatrix} for all values of θ\theta is

[Q16 · Sep · 2017]

Concept 2 of 4

Determinants with complex entries

Intuition

Treat ii like any algebraic symbol but reduce its powers with the cycle i,1,i,1i, -1, -i, 1 (period 4). Expand normally; then collect real and imaginary parts to match a target A+iBA + iB.

Definition

Powers of ii: i1=i, i2=1, i3=i, i4=1i^1 = i,\ i^2 = -1,\ i^3 = -i,\ i^4 = 1, repeating every 4. After expanding a complex determinant, write it as A+iBA + iB and read off AA (real) and BB (imaginary), or solve for unknowns by equating real/imaginary parts.

Powers of i (period 4)

i=i,i2=1,i3=i,i4=1i = i,\quad i^2 = -1,\quad i^3 = -i,\quad i^4 = 1

Worked example

Evaluate 1+i1i1i1+i\begin{vmatrix} 1+i & 1-i \\ 1-i & 1+i\end{vmatrix} where i=1i = \sqrt{-1}.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 2Matrices & DeterminantsHARD
What is the value of the determinant ii2i3i4i6i8i9i12i15\begin{vmatrix}i & i^2 & i^3 \\ i^4 & i^6 & i^8 \\ i^9 & i^{12} & i^{15}\end{vmatrix} where i=1i=\sqrt{-1}?

[Q12 · Apr · 2020]

Concept 3 of 4

Cube-root-of-unity determinants

Intuition

The non-real cube root ω\omega obeys two relations that crush these determinants: ω3=1\omega^3 = 1 and 1+ω+ω2=01 + \omega + \omega^2 = 0. Substitute to reduce powers, then the sum-to-zero relation usually makes a row vanish.

Definition

For a non-real cube root of unity ω\omega: ω3=1\omega^3 = 1 and 1+ω+ω2=01 + \omega + \omega^2 = 0. Reduce every power of ω\omega mod 3, then use the sum relation — a row or column summing to 1+ω+ω21 + \omega + \omega^2 becomes 0, forcing the determinant to 0.

Cube roots of unity

ω3=1,1+ω+ω2=0\omega^3 = 1, \qquad 1 + \omega + \omega^2 = 0

Worked example

If ω=12+i32\omega = -\tfrac12 + i\tfrac{\sqrt3}{2}, evaluate 1+ω1+ω2ωω2\begin{vmatrix}1+\omega & 1+\omega^2\\ \omega & \omega^2\end{vmatrix}.
Practice this concept4 quick reps

From the bank · past-year question

Example 3Matrices & DeterminantsMODERATE
If ω\omega is a non-real cube root of unity, then what is a root of the following equation? x+1ωω2ωx+ω21ω21x+ω=0\begin{vmatrix} x+1 & \omega & \omega^2 \\ \omega & x+\omega^2 & 1 \\ \omega^2 & 1 & x+\omega \end{vmatrix} = 0

[Q12 · Apr · 2025]

Concept 4 of 4

Polynomial and progression determinants

Intuition

If the rows are terms of an AP or GP (or shifted copies), they're linearly dependent and the determinant is 0. When a determinant is set equal to a polynomial ax4+ax^4 + \dots, match powers of xx (or use the degree) to read off a coefficient.

Definition

AP/GP rows: three rows in arithmetic progression satisfy R1+R3=2R2R_1 + R_3 = 2R_2 (dependent) → determinant 0; GP rows are proportional after a log/ratio step → 0. Determinant as polynomial: expand to a polynomial in xx and equate coefficients, or argue the degree to find a specific coefficient.

Worked example

Evaluate 111123149\begin{vmatrix}1 & 1 & 1\\1 & 2 & 3\\1 & 4 & 9\end{vmatrix}.
Practice this conceptself-check · 4 quick reps

From the bank · past-year question

Example 4Matrices & DeterminantsMODERATE
What is the value of the determinant 1!2!3!2!3!4!3!4!5!\begin{vmatrix} 1! & 2! & 3! \\ 2! & 3! & 4! \\ 3! & 4! & 5! \end{vmatrix} ?

[Q11 · Sep · 2019]

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