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SPI Mathematics · Quadratic Equations

Recognising a Quadratic Equation

A quadratic equation is one that can be written as ax² + bx + c = 0 with a not zero, so its highest power of x is 2.

Why this matters

Seven questions in the bank, three EASY and four MODERATE: name the degree, decide which equation is quadratic, or write a word situation as an equation. The trap in every one is deciding from the look of the equation before expanding it, because x² terms on the two sides often cancel.

Concept 1 of 3: Standard form of a quadratic equation

Every quadratic equation can be tidied into one shape: an x² term, an x term and a number, all on one side, with 0 on the other. Once it is in that shape you can read off a, b and c and see that the degree is 2.

Definition

  • Standard form: ax2+bx+c=0ax^2 + bx + c = 0, where a, b, c are real numbers and a≠0a \ne 0.
  • The degree is the highest power of x, so a quadratic has degree 2.
  • b or c may be 0: x2−9=0x^2 - 9 = 0 and x2+4x=0x^2 + 4x = 0 are both quadratic.
  • If a were 0 there would be no x2x^2 term and the equation would be linear.
  • To reach standard form, move every term to one side. A term changes sign when it crosses the = sign.

Standard form

ax2+bx+c=0,a≠0ax^2 + bx + c = 0, \quad a \ne 0

Worked example

Write 3x2−7=2x3x^2 - 7 = 2x in standard form and give a, b and c.
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The same idea in a practice question:

Practice questionEasy

Example 1 · Quadratic Equations · Recognising a Quadratic Equation

5x2+8x+4=2x2+4x+65x^2 + 8x + 4 = 2x^2 + 4x + 6 is a

Thinking b or c must be non-zero

Only a must be non-zero. x2−16=0x^2 - 16 = 0 has b=0b = 0 and is still a quadratic equation of degree 2.

Keeping the sign when a term crosses the = sign

A term changes sign when it moves to the other side: x2=3x+4x^2 = 3x + 4 becomes x2−3x−4=0x^2 - 3x - 4 = 0, not x2+3x+4=0x^2 + 3x + 4 = 0.

Concept 2 of 3: Simplifying both sides before naming the type of equation

An equation can look quadratic and turn out linear, because the x2x^2 on one side cancels the x2x^2 on the other. It can also look like a cubic and turn out quadratic. Expand first, collect on one side, and only then look at the highest power left.

Definition

  • Expand every bracket, move all terms to one side and collect like terms.
  • If the x2x^2 terms cancel and only x is left, the equation is linear.
  • If an x3x^3 term survives, it is a cubic. If the x3x^3 terms cancel and x2x^2 is left, it is quadratic.
  • A term in x\sqrt{x} is not a polynomial term, so such an equation is not quadratic. A number under the root is fine: 2x2\sqrt{2}x^2 is allowed.
  • A term in 1x\frac{1}{x}: multiply every term by the power of x that clears it, then check the degree.

Worked example

Is (x+3)2=x2+4x+1(x + 3)^2 = x^2 + 4x + 1 a quadratic equation?
Practice this conceptself-check · 4 quick reps

The same idea in a practice question:

Practice questionModerate

Example 2 · Quadratic Equations · Recognising a Quadratic Equation

Which of the given equation is not quadratic?

Judging by the look before expanding

An x2x^2 on both sides proves nothing. x(x+3)=x2−5x(x + 3) = x^2 - 5 loses its x2x^2 terms and reduces to 3x+5=03x + 5 = 0, a linear equation.

Confusing a root in the coefficient with a root of x

3x2+x−1=0\sqrt{3}x^2 + x - 1 = 0 is quadratic, because 3\sqrt{3} is just a number. x2+x=1x^2 + \sqrt{x} = 1 is not, because x itself is under the root.

Concept 3 of 3: Writing a word situation as a quadratic equation

A word problem becomes an equation in three moves: call the unknown x, write every other quantity using x, then use the one fact the problem gives (an area, a product, a right angle) to join them with an = sign.

Definition

  • Let the smallest or simplest unknown be x, and write the others from it: '6 more than twice x' is 2x+62x + 6.
  • Rectangle: length ×\times breadth == area.
  • Consecutive integers: x and x+1x + 1.
  • Right triangle: the hypotenuse is the longest side, and its square equals the sum of the squares of the other two sides.

Pythagoras theorem

(hypotenuse)2=(base)2+(height)2(\text{hypotenuse})^2 = (\text{base})^2 + (\text{height})^2

Worked example

The length of a rectangle is 3 m more than its breadth, and its area is 40 m². Write a quadratic equation for the breadth x.
Practice this conceptself-check · 3 quick reps

The same idea in a practice question:

Practice questionModerate

Example 3 · Quadratic Equations · Recognising a Quadratic Equation

The hypotenuse of a right triangle is 6m more than twice the shortest side. The third side is 2m less than the hypotenuse. The representation of the above situation in the form of a quadratic equation is

Adding the hypotenuse to another side

The hypotenuse stands alone on one side: hypotenuse2=a2+b2\text{hypotenuse}^2 = a^2 + b^2. An equation that adds the hypotenuse squared to another side squared is wrong.

Reading 'more than' backwards

'6 more than twice x' is 2x+62x + 6, and '2 less than h' is h−2h - 2. Write the base quantity first, then add or take away.

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