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SSC CGL Maths · Mensuration 3D

Prisms and Pyramids

A prism holds its base area times its height, and its side faces together are the base perimeter times the height. A pyramid on the same base and height holds one third as much.

Why this matters

Twenty-three questions in the bank, sixteen EASY and seven MODERATE, and every one of them comes from the 2025 shifts; the 2023 and 2024 shifts in the bank have none. Most rows are one line once you know two facts, base area times height for a prism and one third of that for a pyramid. The MODERATE ones stack layers whose heights form an AP, which is one addition more.

Concept 1 of 4: Volume of a prism

A prism is one shape stacked straight up: every slice parallel to the base is a copy of the base. So the volume is the base area carried through the height, exactly as for a cuboid, which is the prism with a rectangle for its base.

Definition

  • Volume of a right prism == base area ×\times height.
  • Base areas you will need: an equilateral triangle of side aa has area 34a2\frac{\sqrt{3}}{4}a^2; a right triangle has 12×\frac{1}{2} \times the two shorter sides; a trapezium has 12×\frac{1}{2} \times (sum of the parallel sides) ×\times the distance between them; a regular hexagon of side aa is six equilateral triangles, 332a2\frac{3\sqrt{3}}{2}a^2.
  • With the base unchanged, the volume changes in step with the height: 1.51.5 times the height gives 1.51.5 times the volume.
  • Two prisms of equal height compare as their base areas.
  • A composite tank (one prism on another): find each volume in one unit and add.

Prism and two base areas

V=base area×hA△=34a2Ahexagon=332a2V = \text{base area} \times h \qquad A_{\triangle} = \frac{\sqrt{3}}{4}a^2 \qquad A_{\text{hexagon}} = \frac{3\sqrt{3}}{2}a^2

Worked example

A right prism has an equilateral triangle of side 8 cm as its base and is 5 cm tall. Find its volume.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 13 Sep 2025, Shift 3 · Q72Easy

Example 1 · Mensuration 3D · Prisms and Pyramids

If the base of a prism is a regular hexagon of side 66 cm and the height is 1010 cm, what is its volume?

A hexagon is six triangles

A regular hexagon of side aa splits into six equilateral triangles of side aa, so its area is 6×34a2=332a26 \times \frac{\sqrt{3}}{4}a^2 = \frac{3\sqrt{3}}{2}a^2. Writing 34a2\frac{\sqrt{3}}{4}a^2 alone gives one triangle.

Square centimetres times metres

A base of 60 cm260\ \text{cm}^2 and a height of 1.2 m give 60×120=7200 cm360 \times 120 = 7200\ \text{cm}^3, not 7272. Change the height to centimetres first.

Concept 2 of 4: Lateral surface area of a prism

The side faces of a prism are rectangles, each as tall as the prism. Laid side by side they form one long rectangle whose length is the distance round the base.

Definition

  • Lateral (side) surface == perimeter of the base ×\times height.
  • Total surface == lateral surface +2×+ 2 \times base area.
  • The lateral surface needs only the perimeter. A question that also gives the base area may be testing whether you know that.
  • Base sides given as a ratio with a known perimeter: the lateral surface still needs only the perimeter.

Lateral and total surface of a prism

LSA=perimeter of base×hTSA=LSA+2×base area\text{LSA} = \text{perimeter of base} \times h \qquad \text{TSA} = \text{LSA} + 2 \times \text{base area}

Worked example

A right prism has a triangular base with sides 8 cm, 15 cm and 17 cm, and its height is 10 cm. Find its lateral surface area and its total surface area.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 26 Sep 2025, Shift 1 · Q63Easy

Example 2 · Mensuration 3D · Prisms and Pyramids

A triangular prism has base side lengths 5 cm, 6 cm, and 7 cm and height 10 cm. What is its lateral surface area?

Base area in place of perimeter

The lateral surface multiplies the perimeter of the base by the height. Base area times height is the volume, a different quantity.

Concept 3 of 4: A prism built in layers whose heights form an AP

Every layer sits on the same base, so the whole stack is one prism whose height is all the layer heights added together. The only real work is adding an AP.

Definition

  • Same base in every layer, so volume == base area ×\times (sum of the layer heights).
  • For nn layers running from height aa to height ll: sum =n2(a+l)= \frac{n}{2}(a + l).
  • If you know the first height aa and the step dd, the last height is a+(n−1)da + (n - 1)d.
  • Rising or falling does not matter: only the total height counts.
  • The same rule works for a stack of cylinders of one radius.

Sum of the layer heights

H=n2(a+l)l=a+(n−1)dV=base area×HH = \frac{n}{2}(a + l) \qquad l = a + (n - 1)d \qquad V = \text{base area} \times H

Worked example

A prism with a square base of side 3 cm is built in 6 layers. The bottom layer is 2 cm tall and each layer is 3 cm taller than the one below it. Find the volume.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 20 Sep 2025, Shift 1 · Q65Moderate

Example 3 · Mensuration 3D · Prisms and Pyramids

A prism with a square base of side length 5 cm is constructed in layers. Its height follows an arithmetic progression, increasing from 4 cm in the first layer to 16 cm in the fourth layer. What is the total volume of the prism?

Using one layer's height

The prism is as tall as all its layers together. Base area times the tallest layer, or times the average layer without multiplying by the number of layers, gives only part of the volume.

Concept 4 of 4: Volume and lateral surface of a pyramid

A pyramid on the same base and with the same height as a prism holds exactly one third of it. Its side faces are triangles, each as tall as the slant height.

Definition

  • Volume =13×= \frac{1}{3} \times base area ×\times height. The height is vertical: from the apex straight down to the base.
  • Lateral surface of a regular pyramid =12×= \frac{1}{2} \times perimeter of the base ×\times slant height (the height of each triangular face).
  • For a square base of side aa this is 2al2al.
  • A pyramid set on a cube or a prism: add the two volumes.

Pyramid

V=13×base area×hLSA=12×perimeter×lV = \frac{1}{3} \times \text{base area} \times h \qquad \text{LSA} = \frac{1}{2} \times \text{perimeter} \times l
  • hhvertical height, apex to base
  • llslant height of a face

Worked example

A pyramid has a square base of side 6 cm and a vertical height of 4 cm. The slant height of each face is 5 cm. Find its volume and its lateral surface area.
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 21 Sep 2025, Shift 1 · Q58Easy

Example 4 · Mensuration 3D · Prisms and Pyramids

A company designs a new chocolate box in the shape of a regular right pyramid with a square base. The base side of the box is 10 cm and its height is 12 cm. Due to packaging constraints, the box can only be filled up to 90%90\% of its total volume. If the company wants to estimate the total cost of chocolate, knowing that 1 cm3\text{cm}^3 of chocolate costs ₹0.50, what is the cost of chocolate to fill one such box?

Forgetting the one third

A pyramid is one third of the prism on the same base and height. Base area times height alone gives three times the answer.

Slant height in the volume

A square pyramid of base side 6 cm can have vertical height 4 cm and slant height 5 cm. Use 4 for the volume and 5 for the faces.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (4)

  • Volume of a prism

    Prism and two base areas

    V=base area×hA△=34a2Ahexagon=332a2V = \text{base area} \times h \qquad A_{\triangle} = \frac{\sqrt{3}}{4}a^2 \qquad A_{\text{hexagon}} = \frac{3\sqrt{3}}{2}a^2
  • Lateral surface area of a prism

    Lateral and total surface of a prism

    LSA=perimeter of base×hTSA=LSA+2×base area\text{LSA} = \text{perimeter of base} \times h \qquad \text{TSA} = \text{LSA} + 2 \times \text{base area}
  • A prism built in layers whose heights form an AP

    Sum of the layer heights

    H=n2(a+l)l=a+(n−1)dV=base area×HH = \frac{n}{2}(a + l) \qquad l = a + (n - 1)d \qquad V = \text{base area} \times H
  • Volume and lateral surface of a pyramid

    Pyramid

    V=13×base area×hLSA=12×perimeter×lV = \frac{1}{3} \times \text{base area} \times h \qquad \text{LSA} = \frac{1}{2} \times \text{perimeter} \times l

Watch out for (6)

Test yourself on Mensuration 3D

20 past SSC CGL questions from this chapter, timed at 12 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.