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SSC CGL Reasoning · Inequalities

Inequality Chains

Letters joined by signs such as greater than, less than and equal to; a conclusion about two letters is definitely true only if every sign between them points the same way.

Why this matters

Twelve questions in the bank, all from the 2025 shifts, with 6 EASY and 6 MODERATE. Each is solved by reading the signs between two letters, so one rule, applied with care, answers every one.

Concept 1 of 3: Reading the signs between two letters

Walk from one letter to the other along the chain and read every sign on the way. If all of them point the same way, the two letters are definitely related. If the signs turn round even once, nothing definite can be said.

Definition

  • Same direction: A>B≥CA > B \ge C gives A>CA > C. All the signs point one way, so the relation holds.
  • Strict or not: if at least one sign on the way is strict (>> or <<), the result is strict. If every sign allows equality (≥\ge, ==), the result is ≥\ge or ≤\le.
  • Equal signs never change the direction; they can be passed freely.
  • Opposite directions: A>B<CA > B < C gives no relation between A and C.
  • Statements split by commas or semicolons can be joined through a shared letter: T≥AT \ge A and A≤DA \le D do not join into one direction, but C<AC < A and A≤TA \le T do.
  • Fast route: write just the stretch of the chain between the two letters of a conclusion, and look at the signs alone.

Worked example

Statement: A>B≥C=D>EA > B \ge C = D > E. Conclusions: I. A>EA > E. II. C≥EC \ge E. Which are definitely true?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 19 Sep 2025, Shift 1 · Q7Easy

Example 1 · Inequalities · Inequality Chains

Read the given statement and conclusions carefully. Decide which of the given conclusions is/are definitely TRUE from the statement. Statement: P>Q<S≤T=R≥U>VP > Q < S \le T = R \ge U > V Conclusion I: Q<RQ < R Conclusion II: U>TU > T

Turning ≥\ge into >>

T=R≥UT = R \ge U gives T≥UT \ge U, not T>UT > U: T and U may be equal. Only a strict sign somewhere on the way makes the result strict.

Joining across a sign that turns round

In A≤T<D≥OA \le T < D \ge O, A and O have no fixed relation, because the signs turn at D. Check every sign between the two letters, not just the first and last.

Concept 2 of 3: Either one or the other

Sometimes neither conclusion is definite, yet one of them must be true. That happens when the two conclusions are about the same two letters and, between them, cover every possibility the statement leaves open.

Definition

  • Either-or pair: the two conclusions name the same two letters, neither is definite on its own, and together they cover every case.
  • When the statement gives X≥YX \ge Y: the pair X>YX > Y and X=YX = Y is an either-or pair.
  • When the statement gives no relation at all: the pair X≥YX \ge Y and X<YX < Y is an either-or pair, since one of them must hold.
  • A pair that leaves a case out (X>YX > Y and X<YX < Y, missing X=YX = Y) is not an either-or pair.
  • Fast route: only check for either-or after both conclusions have failed on their own.

Worked example

Statement: M≥N=OM \ge N = O. Conclusions: I. M>OM > O. II. M=OM = O. What follows?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 22 Sep 2025, Shift 3 · Q3Moderate

Example 2 · Inequalities · Inequality Chains

The given statements are followed by two conclusions. Find out which conclusion is TRUE based on the given statements. Statements: J>K=L,M≥N<K,O<J<P,N=Q≥RJ > K = L, M \ge N < K, O < J < P, N = Q \ge R Conclusions: I. M>RM > R II. M=RM = R

Calling any two failed conclusions either-or

Two conclusions about different pairs of letters, or ones that leave a case uncovered, are not an either-or pair. The answer is then neither.

Concept 3 of 3: Coded signs

In some questions each sign is replaced by a symbol, and a table tells you what each symbol means. Decode every statement and conclusion into ordinary signs first; then the chain is read exactly as before.

Definition

1. Copy the table of meanings: for example @ for ≥\ge, # for <<, % for ==. 2. Rewrite every statement with ordinary signs, and join the statements through their shared letters. 3. Rewrite each conclusion the same way and test it with the rules for reading a chain.

  • Fast route: decode the conclusions first; often one of them already contradicts a statement.

Worked example

Here @ means ≥\ge and % means ==. Statements: A @ B, B % C. Conclusion: A @ C. Is it true?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 14 Sep 2025, Shift 2 · Q23Easy

Example 3 · Inequalities · Inequality Chains

In the following questions, the symbols @, #, $\text{\textdollar}, © and % are used with the following meaning as illustrated below: P @ Q ⇒P≥Q\Rightarrow P \ge Q P # Q ⇒P≤Q\Rightarrow P \le Q P $Q⇒P<QP \text{ \textdollar } Q \Rightarrow P < Q P © Q ⇒P>Q\Rightarrow P > Q P % Q ⇒P=Q\Rightarrow P = Q Statements: M © N N # O Conclusions: I. M © O II. M @ O

Reading a symbol by its look

A symbol means only what the table says. Do not guess that @ means greater than because it looks like one; copy the table and use it.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Watch out for (4)

Test yourself on a real paper

Sit a past SSC CGL paper, timed and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.