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AFCAT Numerical Ability · Formula sheet

Clock formulas

15 formulas, 2 reference tables and 31 common traps for AFCAT Numerical Ability Clock, grouped by subtopic.

Full notes with worked examples

How Fast the Hands Turn

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How far a hand turns in a given time

Degrees turned

θhour=30h+0.5m,θminute=6m\theta_{\text{hour}} = 30h + 0.5m, \qquad \theta_{\text{minute}} = 6m

The minute hand gains 5.5° a minute

Time to change the gap

t=θ5.5=2θ11 minutest = \dfrac{\theta}{5.5} = \dfrac{2\theta}{11} \text{ minutes}

The speeds of the two hands

HandOne full turn takesDegrees per hourDegrees per minute
Minute hand60 minutes360°360°6°6°
Hour hand12 hours30°30°0.5°0.5°
Half a degree a minute: in 20 minutes the hour hand moves 10°, a third of the way to the next number.

Common traps

6° a minute is the minute hand

The hour hand covers only 30°30° in a whole hour, so it moves 30÷60=0.5°30 \div 60 = 0.5° a minute. Giving it 6°6° a minute makes it as fast as the minute hand.

Per hour or per minute

The minute hand turns 360°360° an hour and 6°6° a minute. Read the unit in the question before picking, because the options often carry both.

The hour hand is past its number

At 2:40 the hour hand is not on the 2. It has moved 40×0.5=20°40 \times 0.5 = 20° beyond it, so it is 80°80° from 12, not 60°60°.

Count the hours forward

From 10 o'clock to 2 o'clock is 4 hours (10 to 12, then 12 to 2), so the hour hand turns 120°120°. Taking 10−2=810 - 2 = 8 hours counts the wrong way round.

Use 5.5, not 6

The gap does not grow at 6°6° a minute, because the hour hand moves too. From 12:00 a gap of 44°44° takes 44÷5.5=844 \div 5.5 = 8 minutes, not 44÷644 \div 6.

A lap takes more than 60 minutes

In 60 minutes the minute hand gains only 330°330°, short of a full lap. The hands meet every 6551165\tfrac{5}{11} minutes, not every hour.

The Angle Between the Hands at a Given Time

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The angle on the hour

On the hour

θ=30h   or   360−30h\theta = 30h \;\text{ or }\; 360 - 30h

The angle at any time

Angle between the hands

θ=∣30h−5.5m∣\theta = |30h - 5.5m|

Above 180°: the smaller angle and the reflex angle

Smaller and reflex angle

θsmall=min⁡(θ, 360−θ),θreflex=360−θsmall\theta_{\text{small}} = \min(\theta,\ 360 - \theta), \qquad \theta_{\text{reflex}} = 360 - \theta_{\text{small}}

Naming, comparing and changing angles

Change in the angle

Δθ=∣θ2−θ1∣\Delta\theta = |\theta_2 - \theta_1|

Common traps

Count the short way

At 11:00 the hour hand is 11 gaps from 12 one way but only 1 the other. The angle between the hands is 30°30°, not 330°330°.

The hour hand has moved

At 5:40 the hour hand is 20°20° past the 5, at 170°170°. Taking it at 150°150° gives 90°90° instead of the true 70°70°.

Half past is not on the number

At 7:30 the hour hand is halfway between 7 and 8, at 225°225°. The angle is ∣210−165∣=45°|210 - 165| = 45°, not 30°30°.

Above 180 is the long way round

At 12:44 the formula gives 242°242°. The hands are 118°118° apart the short way; 242°242° is the reflex angle, the answer only when the question asks for it.

Reflex is 360 minus the smaller angle

If the smaller angle is 70°70°, the reflex angle is 290°290°. Adding 180 gives 250°250°, which is neither angle.

Work the angles, do not judge the times

6:15 and 6:45 look alike, but the angles are 97.5°97.5° and 67.5°67.5°: one obtuse, one acute.

Near 90 still needs the exact value

An angle of 87.5°87.5° is acute even though it is close to a right angle. Name the type from the worked value, never from a rough picture.

When the Hands Meet, Point Opposite or Form an Angle

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When the hands coincide or point opposite

Coinciding and opposite hands

m=60h11  (together),m=211(30h±180)  (opposite)m = \dfrac{60h}{11} \;\text{(together)}, \qquad m = \dfrac{2}{11}\left(30h \pm 180\right) \;\text{(opposite)}

When the hands are at a given angle

Time for a given angle

m=211(30h±θ)m = \dfrac{2}{11}\left(30h \pm \theta\right)

How many times a position comes round

PositionIn 12 hoursIn 24 hoursHow often
Coinciding1122every 6551165\tfrac{5}{11} min
Not 12 in 12 hours: the meeting between 11 and 12 is 12:00 itself.
Opposite (180°180°)1122every 6551165\tfrac{5}{11} min
In a straight line (together or opposite)2244every 3281132\tfrac{8}{11} min
At right angles2244every 3281132\tfrac{8}{11} min
Not 48 in a day: 3:00 and 9:00 are each shared by two neighbouring hours.
Any other angle between 0°0° and 180°180°2244twice in each lap

Common traps

Eleven meetings, not twelve

The hands meet once in each hour except between 11 and 12, where the meeting is 12:00 itself. That is why a meeting comes every 6551165\tfrac{5}{11} minutes.

A straight line includes together

If a question asks only for 'in a straight line', the moment the hands coincide counts too. Between 1 and 2 that is about 1:05 as well as about 1:38.

Drop a value outside the hour

Between 10 and 11, 211(300+90)=701011\tfrac{2}{11}(300 + 90) = 70\tfrac{10}{11} is past the hour, so only 211(300−90)=38211\tfrac{2}{11}(300 - 90) = 38\tfrac{2}{11} counts.

Minute spaces are not degrees

Hands 5 minute spaces apart are 30°30° apart. Putting θ=5\theta = 5 into the formula answers a different question.

Count a stretch by listing

From 2:00 to 5:00 is 3 hours, but 3×1112=2.753 \times \tfrac{11}{12} = 2.75 is not a count. List the meetings, about 2:11, 3:16 and 4:22, and there are 3.

44 right angles a day, not 48

Two right angles an hour would make 48. Around 3 and 9 the right angles of neighbouring hours fall on the same moment, 3:00 or 9:00, so 12 hours hold 22 and a day 44.

Mirror Images of a Clock

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The image time is 11:60 minus the real time

Mirror time

image=11:60−real time\text{image} = 11{:}60 - \text{real time}

Finding the real time from the image

Real time from the image

real=11:60−image\text{real} = 11{:}60 - \text{image}

Times after 11, time passing and other twists

Reading 0 hours

11:60−11:m=0:(60−m)=12:(60−m)11{:}60 - 11{:}m = 0{:}(60 - m) = 12{:}(60 - m)

Common traps

Subtract from 11:60, not 12:00

Subtracting 2:40 from 12:00 digit by digit tempts you to 10:20. With 11:60 there is nothing to borrow: 11:60−2:40=9:2011{:}60 - 2{:}40 = 9{:}20.

60 minutes is the next hour

11:60−5:00=6:6011{:}60 - 5{:}00 = 6{:}60, which a clock shows as 7:00. Writing 6:60 as the answer matches no option.

The image is not 6 hours off

An image of 1:20 is not 7:20 in real time. Only 12:00 minus the image works: 11:60−1:20=10:4011{:}60 - 1{:}20 = 10{:}40.

Move the real clock, not the image

Two hours ago the image showed 3:10, so the real time then was 8:50 and now it is 10:50. Adding the two hours to the image first gives 5:10, whose reflection is 6:50: wrong, because the image runs backwards.

There is no 0 on the dial

11:60−11:5011{:}60 - 11{:}50 is 0:10, which a 12-hour dial shows as 12:10.

Clocks That Gain or Lose Time

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What a gaining or losing clock shows

Time shown

shown=real±rate×hours\text{shown} = \text{real} \pm \text{rate} \times \text{hours}

When a fast or slow clock shows the right time

Hours until right

t=errorratet = \dfrac{\text{error}}{\text{rate}}

Turning shown time into real time

Shown and real time

real=shown×6060±g\text{real} = \text{shown} \times \dfrac{60}{60 \pm g}

When a faulty clock is right again

Right again after

t=720drift per hour hourst = \dfrac{720}{\text{drift per hour}} \text{ hours}

Common traps

Carry into the hour

A clock 75 minutes ahead at 4:00 PM shows 5:15 PM, not 4:75.

Count the real hours across noon

From 9:00 AM to 2:00 PM is 5 hours. Taking 9−2=79 - 2 = 7 hours counts the wrong way and overstates the drift.

A third of an hour is 20 minutes

6136\tfrac{1}{3} hours is 6 hours 20 minutes, not 6 hours 33 minutes. Multiply the fraction by 60.

A fast clock that gains never catches up

A clock 10 minutes fast that gains 2 minutes an hour only gets further ahead. It looks right again only after gaining a whole 12 hours, the last concept on this page.

The rate is per real hour

A watch gaining 12 minutes an hour shows 6 hours gone. Taking off 6×12=726 \times 12 = 72 minutes gives 4 hours 48 minutes, but those were the watch's hours. The ratio gives 360×6072=300360 \times \tfrac{60}{72} = 300 minutes, exactly 5 hours.

An hour of gain is not enough

A clock 60 minutes ahead shows the wrong hour. Only a gain of 12 hours, 720 minutes, brings both hands back to the right place.

Both gain: subtract the rates

Clocks gaining 5 and 3 minutes an hour pull apart by only 2 minutes an hour, so they match again after 360 hours, not 720÷8=90720 \div 8 = 90.

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