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JEE Mains Maths · Formula sheet

Differentiation formulas

11 formulas and 11 common traps for JEE Mains Maths Differentiation, grouped by subtopic.

Full notes with worked examples

Chain Rule and Inverse-Trig Simplification

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Simplify before you differentiate

A standard substitution

x=tan⁡θ:tan⁡−12x1−x2=2θ=2tan⁡−1x(∣x∣<1)x=\tan\theta:\quad\tan^{-1}\frac{2x}{1-x^2}=2\theta=2\tan^{-1}x\quad(|x|<1)

The chain rule and inverse functions

Derivative of an inverse

g′(k)=1f′(a),f(a)=kg'(k)=\frac{1}{f'(a)},\qquad f(a)=k

Common traps

The branch decides the answer

cos⁡−1(cos⁡x)=x\cos^{-1}(\cos x)=x only on [0,π][0,\pi]. On [π,2π][\pi,2\pi] it is 2π−x2\pi-x, whose derivative is −1-1, not 11. Read the stated interval before you simplify.

Invert at the right point

g′(k)g'(k) is 1f′(a)\frac{1}{f'(a)} where f(a)=kf(a)=k, not 1f′(k)\frac{1}{f'(k)}. Solve f(a)=kf(a)=k first; the root is usually a small integer.

Implicit, Parametric and Logarithmic Differentiation

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Implicit and parametric differentiation

Second derivative, parametric

d2ydx2=ddt(dydx)/dxdt\frac{d^2y}{dx^2}=\frac{d}{dt}\left(\frac{dy}{dx}\right)\Big/\frac{dx}{dt}

Logarithmic differentiation

Variable power

ddxf g=f g(g′ln⁡f+g f′f)\frac{d}{dx}f^{\,g}=f^{\,g}\left(g'\ln f+\frac{g\,f'}{f}\right)

Common traps

Not the ratio of second derivatives

For a parametric curve d2ydx2≠y¨x¨\frac{d^2y}{dx^2}\ne\frac{\ddot y}{\ddot x}. With x=t2, y=t3x=t^2,\ y=t^3 the ratio gives 3t3t, but the true value is 34t\frac{3}{4t}. Differentiate dydx\frac{dy}{dx} with respect to tt, then divide by dxdt\frac{dx}{dt}.

d²x/dy² is not 1/y″

dxdy=1y′\frac{dx}{dy}=\frac{1}{y'}, but d2xdy2=−y′′(y′)3\frac{d^2x}{dy^2}=-\frac{y''}{(y')^3}, not 1y′′\frac{1}{y''}. Differentiate 1y′\frac{1}{y'} with respect to xx, then divide by y′y' once more.

Functional Equations and Derivative Constants

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Functional equations

Derivative from the equation

f(x+y)=f(x)f(y) ⇒ f′(x)=lim⁡h→0f(x)f(h)−1h=f′(0) f(x)f(x+y)=f(x)f(y)\ \Rightarrow\ f'(x)=\lim_{h\to0}f(x)\frac{f(h)-1}{h}=f'(0)\,f(x)

Derivative values as constants

For a cubic

f(x)=x3+ax2+bx+c ⇒ f′(x)=3x2+2ax+b,f′′(x)=6x+2a,f′′′(x)=6f(x)=x^3+ax^2+bx+c\ \Rightarrow\ f'(x)=3x^2+2ax+b,\quad f''(x)=6x+2a,\quad f'''(x)=6

Common traps

Find f(0) first

Most of these equations fix f(0)f(0) before anything else: f(0)=f(0)2f(0)=f(0)^2 gives f(0)=1f(0)=1 when ff never vanishes, and f(0)=2f(0)f(0)=2f(0) gives f(0)=0f(0)=0. Skipping it leaves an unknown constant in the answer.

The coefficient is not a function

f′(1)f'(1) is a number, so x2f′(1)x^2f'(1) differentiates to 2xf′(1)2xf'(1). Treating f′(1)f'(1) as a function of xx and using the product rule gives wrong equations.

Differentiability of Piecewise Functions

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Where two pieces join

Smooth join at x = a

f1(a)=f2(a)andf1′(a)=f2′(a)f_1(a)=f_2(a)\quad\text{and}\quad f_1'(a)=f_2'(a)

Composites and running maxima

Chain rule at a point

(g∘f)′(a)=g′(f(a)) f′(a)when both derivatives exist(g\circ f)'(a)=g'\big(f(a)\big)\,f'(a)\quad\text{when both derivatives exist}

The derivative from its definition

Derivative at a point

f′(a)=lim⁡h→0f(a+h)−f(a)hf'(a)=\lim_{h\to0}\frac{f(a+h)-f(a)}{h}

Common traps

Continuity comes first

Matching slopes is not enough. xx for x<0x<0 and x+1x+1 for x≥0x\ge0 have slope 1 on both sides but jump at 0, so the function is not differentiable there. Write both equations.

A bad inner function can be smoothed out

∣x∣|x| has a corner at 0, but ∣x∣2=x2|x|^2=x^2 is smooth. Test g∘fg\circ f itself at each suspect point; do not assume it fails because ff does.

f′ can exist without being continuous

For x2sin⁡1xx^2\sin\frac1x, the formula for f′(x)f'(x) has no limit at 0, but f′(0)=0f'(0)=0 from the definition. Never decide differentiability at a point by taking the limit of the derivative formula.

Counting Points of Non-Differentiability

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Corners of modulus, max and min

Slope jump at a corner

k ∣x−a∣:f′(a+)−f′(a−)=2kk\,|x-a|:\quad f'(a^+)-f'(a^-)=2k

Jumps of the greatest integer function

Greatest integer function

[x]=n  for  n≤x<n+1,[x+n]=[x]+n  (n∈Z)[x]=n\ \text{ for }\ n\le x<n+1,\qquad[x+n]=[x]+n\ \ (n\in\mathbb{Z})

Common traps

A candidate is not yet a corner

Every zero inside a modulus is only a candidate. ∣x−1∣sin⁡∣x−1∣|x-1|\sin|x-1| and e∣(x−1)2∣e^{|(x-1)^2|} are smooth at 1, and a factor that vanishes at the same point removes the corner. Test each candidate before counting it.

A jump counts twice in m + n

When a question asks for the points where ff is not continuous (mm) and not differentiable (nn), a jump belongs to both counts. Add every jump to nn as well as to mm.

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