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JEE Mains Maths · Formula sheet

Limits and Continuity formulas

18 formulas and 18 common traps for JEE Mains Maths Limits and Continuity, grouped by subtopic.

Full notes with worked examples

Standard Limits and Algebraic Forms

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The standard limits

Standard limits

lim⁡x→0sin⁡xx=1,lim⁡x→01−cos⁡xx2=12,lim⁡x→0ex−1x=1\lim_{x\to0}\frac{\sin x}x=1,\quad\lim_{x\to0}\frac{1-\cos x}{x^2}=\frac12,\quad\lim_{x\to0}\frac{e^x-1}x=1

Factorise or rationalise

Conjugate

p−q=p−qp+q\sqrt p-\sqrt q=\frac{p-q}{\sqrt p+\sqrt q}

Common traps

Match the argument exactly

sin⁡3xx\frac{\sin3x}x tends to 3, not 1: the angle and the denominator must be the same before the standard limit applies. Multiply and divide to make them match.

Rationalise the right part

Multiply by the conjugate of the surd that causes the 0, and keep the other factor. Rationalising a denominator that is not zero only adds work.

Series Expansions and Unknown Constants

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Limits by series expansion

Key expansions

sin⁡x=x−x36+⋯ ,cos⁡x=1−x22+⋯ ,ex=1+x+x22+⋯\sin x=x-\tfrac{x^3}{6}+\cdots,\quad\cos x=1-\tfrac{x^2}{2}+\cdots,\quad e^x=1+x+\tfrac{x^2}{2}+\cdots

Constants that make a limit finite

Matching coefficients

f(x)=c0+c1x+⋯: lim⁡x→0f(x)xn finite⇒c0=⋯=cn−1=0f(x)=c_0+c_1x+\dots:\ \lim_{x\to0}\frac{f(x)}{x^n}\ \text{finite}\Rightarrow c_0=\dots=c_{n-1}=0

Common traps

Expand far enough

Stop too early and everything cancels, leaving 00\frac00 again. Expand each function to the power of xx in the denominator.

Finite is not the same as zero

The lower coefficients must vanish; the xnx^n coefficient need not. Setting it to zero as well answers a different question.

Exponential Limits (1 to the Power Infinity)

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The 1^∞ formula at a point

1 to the power infinity

lim⁡f(x)g(x)=elim⁡g(x) (f(x)−1)(f→1, g→∞)\lim f(x)^{g(x)}=e^{\lim g(x)\,(f(x)-1)}\quad(f\to1,\ g\to\infty)

The 1^∞ formula at infinity

The e limit

lim⁡n→∞(1+an)bn=eab\lim_{n\to\infty}\left(1+\frac an\right)^{bn}=e^{ab}

Common traps

Is it really 1 to the infinity?

If the base tends to something other than 1, the limit is just (base limit)^(power limit) or 0 or infinity. Apply the formula only when the base tends to 1.

The product can tend to 0

In (1+1n2)n\left(1+\frac1{n^2}\right)^n, g(f−1)=1n→0g(f-1)=\frac1n\to0, so the limit is e0=1e^0=1. Compute the product; do not assume it gives ee.

Limits at Infinity and Limits of Sums

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The dominant terms

Leading terms

lim⁡x→∞anxn+…bnxn+…=anbn\lim_{x\to\infty}\frac{a_nx^n+\dots}{b_nx^n+\dots}=\frac{a_n}{b_n}

Sum first, then take the limit

Power sums

∑k=1nk2=n(n+1)(2n+1)6\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6

Sums as integrals

Riemann sum

lim⁡n→∞1n∑k=1nf ⁣(kn)=∫01f(x) dx\lim_{n\to\infty}\frac1n\sum_{k=1}^{n}f\!\left(\frac kn\right)=\int_0^1f(x)\,dx

Common traps

Infinity minus infinity is not 0

x2+x−x\sqrt{x^2+x}-x tends to 12\frac12, not 0. Rationalise before comparing.

Many small terms can add to something

Each term kn2\frac k{n^2} tends to 0, but there are nn of them and their sum tends to 12\frac12. Sum first.

Find the right limits of integration

The limits come from where kn\frac kn starts and ends. If kk runs from nn to 3n3n, the integral is over [1,3][1,3].

Limits via Derivatives and Integrals

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Limits that are derivatives

Derivative as a limit

f′(a)=lim⁡x→af(x)−f(a)x−af'(a)=\lim_{x\to a}\frac{f(x)-f(a)}{x-a}

Limits of integrals

Leibniz rule

ddx∫au(x)g(t) dt=g(u(x)) u′(x)\frac{d}{dx}\int_a^{u(x)}g(t)\,dt=g\big(u(x)\big)\,u'(x)

Common traps

Check the form before L'Hospital

L'Hospital's rule needs 00\frac00 or ∞∞\frac\infty\infty. Applied to a determinate form it gives a wrong answer.

Chain rule on the limit

Differentiating ∫0x2g(t) dt\int_0^{x^2}g(t)\,dt gives g(x2)⋅2xg(x^2)\cdot2x, not g(x2)g(x^2). The factor u′(x)u'(x) is easy to drop.

Greatest Integer and One-Sided Limits

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The greatest integer function

Greatest integer bounds

t−1<[t]≤tt-1<[t]\le t

Left and right limits

Existence of a limit

lim⁡x→af exists ⇐ lim⁡x→a−f=lim⁡x→a+f\lim_{x\to a}f\ \text{exists}\ \Leftarrow\ \lim_{x\to a^-}f=\lim_{x\to a^+}f

Common traps

Values near an integer from above

[cos⁡x][\cos x] near 0 is 0, because cos⁡x\cos x is just below 1, not equal to it. Ask on which side of the integer the inside approaches.

sin|x| over x

sin⁡∣x∣x\frac{\sin|x|}x tends to 1 from the right and −1-1 from the left. A limit that uses ∣x∣|x| or x2\sqrt{x^2} needs both sides checked.

Continuity at a Point

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Matching the two sides

Continuity

lim⁡x→a−f(x)=lim⁡x→a+f(x)=f(a)\lim_{x\to a^-}f(x)=\lim_{x\to a^+}f(x)=f(a)

Using continuity

Intermediate value theorem

f(a) f(b)<0 ⇒ f(c)=0 for some c∈(a,b)f(a)\,f(b)<0\ \Rightarrow\ f(c)=0\ \text{for some}\ c\in(a,b)

Common traps

Use the right formula on each side

The left limit uses the piece defined for x<ax<a, and the value f(a)f(a) uses whichever piece includes aa. Mixing them gives a wrong equation.

No sign change, no guarantee

If f(a)f(a) and f(b)f(b) have the same sign, the theorem says nothing: there may be two roots or none.

Counting Discontinuities and Non-Differentiability

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Jumps and corners

Where the greatest integer jumps

[g(x)] can break only where g(x)∈Z[g(x)]\ \text{can break only where}\ g(x)\in\mathbb Z

Compositions

Candidate points

{x:g breaks}∪{x:g(x) is a break of f}\{x:g\ \text{breaks}\}\cup\{x:g(x)\ \text{is a break of}\ f\}

Functions defined as a limit

Powers in the limit

lim⁡n→∞x2n={0,∣x∣<11,∣x∣=1∞,∣x∣>1\lim_{n\to\infty}x^{2n}=\begin{cases}0,&|x|<1\\1,&|x|=1\\\infty,&|x|>1\end{cases}

Common traps

A zero factor can hide a jump

In x[x]x[x] at 0 the jump of [x][x] is multiplied by 0, so the product is continuous. Test each candidate point; do not just count the integer crossings.

Also where the inside lands on a bad point

Checking only where gg breaks misses the points where g(x)g(x) equals a break of ff. Solve g(x)=g(x)= each bad point of ff.

Compute the boundary separately

At x=±1x=\pm1 the power x2nx^{2n} is exactly 1, giving a third value. Leaving the boundary out misses the break.

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