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CDS Mathematics · Surds, Indices and Simplification

Laws of Indices

Powers of the same base multiply by adding exponents and nest by multiplying them; when several powers are equal, call the common value k.

Why this matters

Sixteen PYQs, the largest page in the chapter. They fall into three kinds: chains like x = y^a, y = z^b that close up into one exponent equation; the a^x = b^y = c^z family, solved by naming the common value; and comparisons of large powers, solved by raising to a common power.

Concept 1 of 3: The index laws

Everything follows from counting factors: amana^m a^n is m+nm + n factors, (am)n(a^m)^n is mnmn factors. Rewrite every term with one base, add or multiply the exponents, and compare.

Definition

  • aman=am+na^m a^n = a^{m + n}, aman=am−n\dfrac{a^m}{a^n} = a^{m - n}, (am)n=amn(a^m)^n = a^{mn}, a0=1a^0 = 1, a−n=1ana^{-n} = \dfrac{1}{a^n}, an=a1/n\sqrt[n]{a} = a^{1/n}.
  • If am=ana^m = a^n with a>0a > 0, a≠1a \ne 1, then m=nm = n.
  • Chains: x=yax = y^a, y=zby = z^b, z=xcz = x^c give x=xabcx = x^{abc}, so abc=1abc = 1.
  • Nested radicals: work from the inside, xx=x3/4\sqrt{x\sqrt x} = x^{3/4}.

Index laws

aman=am+n,(am)n=amn,a−n=1ana^m a^n = a^{m + n}, \quad (a^m)^n = a^{mn}, \quad a^{-n} = \dfrac{1}{a^n}

Worked example

Simplify (xaxb)a+b(xbxc)b+c(xcxa)c+a\left(\dfrac{x^a}{x^b}\right)^{a + b}\left(\dfrac{x^b}{x^c}\right)^{b + c}\left(\dfrac{x^c}{x^a}\right)^{c + a}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2018 · CDS (I) 2018 — Elementary Mathematics · Q4Moderate

Example 1 · Surds, Indices and Simplification · Laws of Indices

If 2b=a+c2b = a + c and y2=xzy^2 = xz, then what is xb−cyc−aza−bx^{b-c} y^{c-a} z^{a-b} equal to?

The base must not be 1

xp=xqx^{p} = x^{q} gives p=qp = q only if x≠1x \ne 1 (and x>0x > 0). That is why the stems add 'x≠1x \ne 1', and why x=1x = 1 is often an extra solution of an index equation.

Concept 2 of 3: When several powers are equal

If ax=by=cza^x = b^y = c^z, call the common value kk. Then a=k1/xa = k^{1/x}, b=k1/yb = k^{1/y}, c=k1/zc = k^{1/z}, and any relation between aa, bb, cc becomes a relation between the reciprocals of the exponents.

Definition

Let ax=by=cz=ka^x = b^y = c^z = k (with k≠1k \ne 1):

  • abc=1abc = 1 gives 1x+1y+1z=0\dfrac1x + \dfrac1y + \dfrac1z = 0;
  • b2=acb^2 = ac gives 2y=1x+1z\dfrac2y = \dfrac1x + \dfrac1z;
  • c=abc = ab gives 1z=1x+1y\dfrac1z = \dfrac1x + \dfrac1y, so z=xyx+yz = \dfrac{xy}{x + y}.
  • A product of prime powers equal to another fixes the exponents: 43x47y=43247243^x 47^y = 43^2 47^2 gives x=y=2x = y = 2.

Common value k

ax=by=cz=k  ⇒  a=k1/x, b=k1/y, c=k1/za^x = b^y = c^z = k \;\Rightarrow\; a = k^{1/x},\ b = k^{1/y},\ c = k^{1/z}

Worked example

If 2x=5y=10z2^x = 5^y = 10^z, find zz in terms of xx and yy.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2019 · CDS (II) 2019 — Elementary Mathematics · Q37Moderate

Example 2 · Surds, Indices and Simplification · Laws of Indices

If 3x=4y=12z3^x = 4^y = 12^z, then z is equal to

Reciprocals of the exponents, not the exponents

10=2×510 = 2\times 5 gives 1z=1x+1y\dfrac1z = \dfrac1x + \dfrac1y, not z=x+yz = x + y. Products of the bases become SUMS of the reciprocal exponents.

Concept 3 of 3: Comparing powers and roots

To compare 2\sqrt2, 33\sqrt[3]{3}, 66\sqrt[6]{6}, raise all of them to the same power so the roots disappear. To compare huge powers, bring them to the same exponent or compare their logarithms.

Definition

  • For positive numbers, raising to the same positive power keeps the order.
  • Roots: raise to the LCM of the root indices.
  • Powers: bring to a common exponent, e.g. 230=8102^{30} = 8^{10} and 320=9103^{20} = 9^{10}, so 320>2303^{20} > 2^{30}.
  • A larger exponent usually beats a larger base: compare nlog⁡an\log a.

Common exponent

amn=(am)na^{mn} = (a^m)^n

Worked example

Order 43\sqrt[3]{4}, 3\sqrt{3} and 106\sqrt[6]{10}.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2020 · CDS (I) 2020 — Elementary Mathematics · Q20Moderate

Example 3 · Surds, Indices and Simplification · Laws of Indices

If x=2x = \sqrt{2}, y=33y = \sqrt[3]{3} and z=66z = \sqrt[6]{6}, then which one of the following is correct ?

Raise every number to the same power

Comparing 2\sqrt2 and 33\sqrt[3]3 by squaring one and cubing the other proves nothing. Use one exponent, the LCM of the root indices, for all of them.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (3)

  • The index laws

    Index laws

    aman=am+n,(am)n=amn,a−n=1ana^m a^n = a^{m + n}, \quad (a^m)^n = a^{mn}, \quad a^{-n} = \dfrac{1}{a^n}
  • When several powers are equal

    Common value k

    ax=by=cz=k  ⇒  a=k1/x, b=k1/y, c=k1/za^x = b^y = c^z = k \;\Rightarrow\; a = k^{1/x},\ b = k^{1/y},\ c = k^{1/z}
  • Comparing powers and roots

    Common exponent

    amn=(am)na^{mn} = (a^m)^n

Watch out for (3)

Test yourself on Surds, Indices and Simplification

20 past CDS questions from this chapter, timed at 24 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.