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CDS Mathematics · Surds, Indices and Simplification

Simplifying Surd Expressions

When x is built from cube roots, name the cube root and use its cube; when an expression holds square roots of squares, remember √(a²) = |a|.

Why this matters

Six PYQs, three of them HARD. The hard ones all use one idea: if u = ∛2, then u³ = 2, so any polynomial in x = 2 + u + u² reduces to a number. The rest are careful expansions.

Concept 1 of 2: Expressions built from cube roots

An xx made of 23\sqrt[3]{2} and its square looks hopeless to cube directly. Move the plain number to the other side, cube both sides, and replace every u3u^3 by 22: the surds either cancel or rebuild xx itself.

Definition

  • Let u=a3u = \sqrt[3]{a}, so u3=au^3 = a.
  • If x−c=u+u2x - c = u + u^2, then (x−c)3=u3(1+u)3=a(1+3u+3u2+u3)(x - c)^3 = u^3(1 + u)^3 = a(1 + 3u + 3u^2 + u^3), which is a(1+a)+3a(x−c)a(1 + a) + 3a(x - c).
  • Expand the cubic asked for and compare.
  • For square roots, x=2+32x = 2 + 3\sqrt2 satisfies (x−2)2=18(x - 2)^2 = 18, a quadratic.

Cube with u³ = a

(u+u2)3=u3(1+u)3=a (1+u)3(u + u^2)^3 = u^3(1 + u)^3 = a\,(1 + u)^3

Worked example

If x=1+33+93x = 1 + \sqrt[3]{3} + \sqrt[3]{9}, find x3−3x2−6xx^3 - 3x^2 - 6x.
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2018 · CDS (II) 2018 — Elementary Mathematics · Q3Hard

Example 1 · Surds, Indices and Simplification · Simplification of Expressions

If x=2+22/3+21/3x = 2 + 2^{2/3} + 2^{1/3}, then the value of the expression x3−6x2+6xx^3 - 6x^2 + 6x will be

Move the whole number before cubing

Cubing x=2+u+u2x = 2 + u + u^2 directly produces dozens of terms. Cubing x−2=u+u2x - 2 = u + u^2 produces four, because u3u^3 factors out.

Concept 2 of 2: Square roots of squares and products of sums

a2\sqrt{a^2} is the size of aa, never negative. And a product of four brackets like (a+b+c)(a+b−c)…(a + b + c)(a + b - c)\ldots pairs up into differences of squares.

Definition

  • a2=∣a∣\sqrt{a^2} = |a|, so (a−b)2+(b−a)2=2∣a−b∣\sqrt{(a - b)^2} + \sqrt{(b - a)^2} = 2|a - b|.
  • (a+b+c)(a+b−c)=(a+b)2−c2(a + b + c)(a + b - c) = (a + b)^2 - c^2.
  • (a+b+c)(−a+b+c)(a−b+c)(a+b−c)=2a2b2+2b2c2+2c2a2−a4−b4−c4(a + b + c)(-a + b + c)(a - b + c)(a + b - c) = 2a^2b^2 + 2b^2c^2 + 2c^2a^2 - a^4 - b^4 - c^4.
  • Mixed numbers under a root: convert first, 338=2783\tfrac{3}{8} = \dfrac{27}{8}.

Root of a square

a2=∣a∣\sqrt{a^2} = |a|

Worked example

Evaluate (2+3+1)(2+3−1)(\sqrt2 + \sqrt3 + 1)(\sqrt2 + \sqrt3 - 1).
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

CDS · 2026 · CDS (II) 2026 — Elementary Mathematics · Q19Hard

Example 2 · Surds, Indices and Simplification · Simplification of Expressions

What is (2+3+5)(2+3−5)(2−3+5)(−2+3+5)(\sqrt{2} + \sqrt{3} + \sqrt{5})(\sqrt{2} + \sqrt{3} - \sqrt{5})(\sqrt{2} - \sqrt{3} + \sqrt{5})(-\sqrt{2} + \sqrt{3} + \sqrt{5}) equal to ?

√(a²) is not a

(a−b)2=∣a−b∣\sqrt{(a - b)^2} = |a - b|, which is b−ab - a when b>ab > a. Writing a−ba - b makes a positive quantity look negative.

Summary — formulas & gotchas at a glance

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Test yourself on Surds, Indices and Simplification

20 past CDS questions from this chapter, timed at 24 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.