PYQ Vault

JEE Mains Maths · Trigonometric Equations

Exponential, Bounded and Graphical Equations

Equations that are not a polynomial in one ratio: powers with a trigonometric exponent, sides that meet only at their bounds, a line against the tangent graph, and moduli.

Why this matters

Thirteen PYQs, ten of them multiple choice. Four put sin², cos², tan² or sec² in an exponent and become an equation in one power; nine have no algebraic route, so they compare bounds on the two sides, draw a line against the tangent graph, use a function that only increases, or split a modulus by sign. Two ideas cover the page.

Concept 1 of 2: Powers with sin² and cos² in the exponent

In asin⁡2x+acos⁡2xa^{\sin^2x}+a^{\cos^2x} the exponents add to 1, so with t=asin⁡2xt=a^{\sin^2x} the second term is at\frac at. The equation becomes a quadratic in tt. Each root gives a value of sin⁡2x\sin^2x, which must lie in [0,1][0,1]. The same works for tan⁡2x\tan^2x and sec⁡2x\sec^2x, which differ by 1.

Definition

  • acos⁡2x=aasin⁡2xa^{\cos^2x}=\frac{a}{a^{\sin^2x}} and asec⁡2x=a⋅atan⁡2xa^{\sec^2x}=a\cdot a^{\tan^2x}.
  • For a>1a>1, t=asin⁡2xt=a^{\sin^2x} lies in [1,a][1,a]; keep only roots in that range.
  • Then sin⁡2x=log⁡at\sin^2x=\log_at; count the angles as usual.

Substitution

t=asin⁡2x:asin⁡2x+acos⁡2x=t+att=a^{\sin^2x}:\qquad a^{\sin^2x}+a^{\cos^2x}=t+\frac at

Worked example

How many solutions has 4sin⁡2x+4cos⁡2x=54^{\sin^2x}+4^{\cos^2x}=5 in [0,2π][0,2\pi]?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2023 · 10 April 2023 · Q165Moderate

Example 1 · Trigonometric Equations · Exponential, Bounded and Graphical Equations

Let S={x∈(−π2,π2):91−tan⁡2x+9tan⁡2x=10}S =\left\{ x \in\left( -\frac{\pi}{2},\frac{\pi}{2} \right):9^{1 -\tan^{2}x}+9^{\tan^{2}x}= 10 \right\} and β=∑x∈Stan⁡2(x3)\beta =\sum_{x \in S} \tan^{2}\left( \frac{x}{3} \right), then 16(β−14)2\frac{1}{6}(\beta - 14)^{2} is equal to

A root in t may be out of range

For a>1a>1, t=asin⁡2xt=a^{\sin^2x} lies in [1,a][1,a]. A root of the quadratic outside that range gives no angle, just as sin⁡x=2\sin x=2 gives none.

Concept 2 of 2: Bounds, graphs and moduli

Some equations have no algebraic route. If one side is at most 2 and the other at least 2, both must equal 2 at the same point. If a line meets tan⁡x\tan x, count one crossing per full branch and check the part-branches at the ends. If a function only increases, it has at most one root. A modulus is split by sign, and each root is kept only if it has the sign its case assumed.

Definition

  • Bounds: 2cos⁡u≤22\cos u\le2 and ax+a−x≥2a^x+a^{-x}\ge2, with equality only at x=0x=0.
  • sin⁡7x+cos⁡7x≤sin⁡2x+cos⁡2x=1\sin^7x+\cos^7x\le\sin^2x+\cos^2x=1, with equality only when one of sin⁡x,cos⁡x\sin x,\cos x is 1 and the other 0.
  • A decreasing line meets each full branch of tan⁡x\tan x exactly once.
  • f′>0f'>0 throughout: at most one root, and exactly one if ff changes sign.
  • ∣u∣=v|u|=v: solve u=vu=v where u≥0u\ge0 and −u=v-u=v where u<0u<0; keep roots that fit their case.

Forced equality

f(x)≤m≤g(x) for all x:f(x)=g(x) exactly when f(x)=g(x)=mf(x)\le m\le g(x)\ \text{for all}\ x:\quad f(x)=g(x)\ \text{exactly when}\ f(x)=g(x)=m

Worked example

How many real xx satisfy 2sin⁡x=3x+3−x2\sin x=3^x+3^{-x}?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

JEE Mains · 2025 · 3 Apr 2025 · Q60Moderate

Example 2 · Trigonometric Equations · Exponential, Bounded and Graphical Equations

The number of solutions of the equation 2x+3tan⁡x=π,x∈[−2π,2π]−2x+ 3\tan x=\pi,x\in\left\lbrack - 2\pi,2\pi \right\rbrack- {±π2,±3π2}\left\{ \pm\frac{\pi}{2}, \pm\frac{3\pi}{2} \right\} is.

Check the part-branches at the ends

A full branch of tan⁡x\tan x always meets a decreasing line once. A part-branch at the edge of the interval may or may not: compare the line's values there with the range that tan⁡x\tan x covers on that piece.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (2)

  • Powers with sin² and cos² in the exponent

    Substitution

    t=asin⁡2x:asin⁡2x+acos⁡2x=t+att=a^{\sin^2x}:\qquad a^{\sin^2x}+a^{\cos^2x}=t+\frac at
  • Bounds, graphs and moduli

    Forced equality

    f(x)≤m≤g(x) for all x:f(x)=g(x) exactly when f(x)=g(x)=mf(x)\le m\le g(x)\ \text{for all}\ x:\quad f(x)=g(x)\ \text{exactly when}\ f(x)=g(x)=m

Watch out for (2)

Test yourself on Trigonometric Equations

15 past JEE Mains questions from this chapter, timed at 36 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.