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SSC CGL Maths · Time and Work

Work Rates

A worker who finishes a job in n days does one n-th of it each day, so rates add when people work together and subtract when you need one worker's share.

Why this matters

Fifty-two questions in the bank, forty-six of them EASY: two or three people working together, one worker found from a team, the part of the job left after a few days, and pay shared by work done. Every later page in this chapter reuses the one-day rate, so make it automatic here.

Concept 1 of 4: Workers together: add the one-day rates

If Ravi paints a wall in 6 days, he paints a sixth of it each day. Two painters on the same wall each add their own share every day, so you add what each one does in a day. You never add the days.

Definition

  • One day's work: a worker who needs nn days does 1n\frac{1}{n} of the job each day. Hours and minutes work the same way.
  • Together: add the rates. Time together =1÷= 1 \div (sum of the rates).
  • Two workers, fast route: time together =aba+b= \frac{ab}{a + b}, product over sum. It is safe for exactly two workers only.
  • LCM units, fast route: take the job as the LCM of the given times. Each worker's daily units are that LCM divided by their own time, always whole numbers, and the time is units divided by the daily total. This is the quickest way for three workers.
  • Output jobs (pages typed, items made) work the same way with real units: pages per hour add.

Working together

Rate=1nT=aba+bT=11a+1b+1c\text{Rate} = \frac{1}{n} \qquad T = \frac{ab}{a + b} \qquad T = \frac{1}{\frac{1}{a} + \frac{1}{b} + \frac{1}{c}}
  • ndays one worker needs alone
  • a, b, cdays each worker needs alone
  • Tdays needed when they work together

Worked example

P can finish a job in 12 days, Q in 20 days and R in 30 days. How many days do all three take working together?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2023 · Tier I, 17 Jul 2023, Shift 1 · Q60Easy

Example 1 · Time and Work · Work Rates

A, B and C, working alone, can complete a job in 16, 24 and 36 days, respectively. In how many days can they complete the job if they work together?

Adding the days instead of the rates

Two workers taking 10 and 15 days do not take 25 days together, nor 12.5 days (the average). Together is always quicker than the faster worker alone: here 10×1525=6\frac{10 \times 15}{25} = 6 days.

Using product over sum for three workers

abca+b+c\frac{abc}{a + b + c} is not the time for three workers. For 12, 20 and 30 days it gives about 116 days, while the true time is 6. For three or more workers, add the rates or use LCM units.

Concept 2 of 4: Part of the job done in a given time

Work done is rate times time, just as distance is speed times time. If the whole job takes 20 days, 5 days of it finish a quarter. Running the other way, if part of a job took some days, scale up to find the whole.

Definition

  • Work done == rate ×\times time =tn= \frac{t}{n} for a worker who needs nn days and works tt days.
  • Work left =1−= 1 - work done. For a team, use the team's daily rate, the sum of its members' rates.
  • Part known, whole wanted: if a fraction ff of the job takes dd days, the whole job takes df\frac{d}{f} days, and any other fraction gg takes df×g\frac{d}{f} \times g days.
  • Fast route: when two workers are described by the parts they finish in the SAME number of days, add the parts directly. There is no need to find each whole time.

Work done and work left

W=tnLeft=1−WWhole time=dfW = \frac{t}{n} \qquad \text{Left} = 1 - W \qquad \text{Whole time} = \frac{d}{f}
  • tdays worked
  • ndays the worker needs for the whole job
  • Wfraction of the job done
  • ffraction of the job finished in d days
  • ddays taken for that fraction

Worked example

P can finish a job in 10 days and Q in 14 days. They work together for 5 days. What fraction of the job is left?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 12 Sep 2025, Shift 1 · Q66Easy

Example 2 · Time and Work · Work Rates

A is able to complete a task in 15 days, while B takes 20 days to finish the same task. If they collaborate and work together for 4 days, what fraction of the work will still remain?

Marking the part done when the part left is asked

If a team does 58\frac{5}{8} of a job in the days given, the part left is 38\frac{3}{8}. SSC usually prints both fractions among the options, so read the last line of the question again before marking.

Scaling the days the wrong way

If 34\frac{3}{4} of a job takes 18 days, the whole takes 18÷34=2418 \div \frac{3}{4} = 24 days, not 18×34=13.518 \times \frac{3}{4} = 13.5. The whole job always takes longer than any part of it.

Concept 3 of 4: One worker's time from the team's time

A team's rate is the sum of its members' rates. Take away the members you know and what remains is the unknown worker's rate. When only pairs are given, each person sits in two of the pairs, so the three pair rates add to twice the whole team.

Definition

  • One worker missing: rate of the missing worker == team rate −- the known rates.
  • Two people, fast route: if the pair takes aa days and the known worker bb days (b>ab > a), the other takes abb−a\frac{ab}{b - a} days.
  • Pages or units: subtract pages per hour the same way, then time == pages ÷\div pages per hour.
  • Three pairs given (A and B, B and C, C and A): add the three pair rates. The sum is twice the rate of all three, so halve it, then take away a pair to get one person.
  • LCM units keep every step in whole numbers: take the job as the LCM of the pair times.

Finding one worker

x=abb−aA+B+C=(A+B)+(B+C)+(C+A)2x = \frac{ab}{b - a} \qquad A + B + C = \frac{(A + B) + (B + C) + (C + A)}{2}
  • adays the pair takes together
  • bdays the known worker takes alone
  • xdays the other worker takes alone
  • A,B,CA, B, Ceach worker's one-day rate

Worked example

A and B together can finish a job in 10 days. A alone takes 15 days. How long does B take alone?
Practice this conceptself-check · 4 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 13 Sep 2025, Shift 2 · Q66Easy

Example 3 · Time and Work · Work Rates

A can lay railway track between two specified stations in 16 days, while B can complete the same task in 12 days. When C assists them, they manage to finish the job in just 4 days. How long would it take for C to complete the job on their own?

Forgetting to halve the pair total

When the times of A and B, B and C, and C and A are given, the sum of the three pair rates is twice the rate of all three, because each person appears in two pairs. Not halving doubles the team's speed and halves its time.

Subtracting the times

If a pair takes 10 days and one of them 15 days, the other does not take 5 days. Subtract rates: 110−115=130\frac{1}{10} - \frac{1}{15} = \frac{1}{30}, so 30 days.

Concept 4 of 4: Sharing the pay by work done

The money is paid for the job, not for the days spent on it. Each person gets the same share of the money as the share of the work they did.

Definition

  • Share of the pay == share of the work done ×\times total pay.
  • Everyone works the whole time: shares are in the ratio of the rates, 1a:1b:1c\frac{1}{a} : \frac{1}{b} : \frac{1}{c}. LCM units give this ratio at once as whole numbers.
  • A helper joins: find what the named workers did in the days worked. The helper's share of the work is 1 minus theirs.
  • Days matter only through the work they produce: a slow worker who works many days can earn more than a fast one who works a few.

Pay shared by work

Share=work donewhole job×total pay\text{Share} = \frac{\text{work done}}{\text{whole job}} \times \text{total pay}

Worked example

A can finish a job in 6 days, B in 9 days and C in 18 days. They do it together and are paid ₹4,200. What is B's share?
Practice this conceptself-check · 3 quick reps

The same idea in a real exam question:

SSC CGL · 2025 · Tier I, 14 Sep 2025, Shift 3 · Q62Moderate

Example 4 · Time and Work · Work Rates

A alone can complete a job in 12 days and B alone in 18 days. A and B agree to do the work for ₹ 7,200. With C's help they finish it in 5 days. How much should C be paid?

Sharing the pay in the ratio of days

Pay follows work, so it is shared in the ratio of the rates, which is the inverse of the days. When both work the whole time, a worker who needs 10 days earns more than one who needs 15.

Giving a helper an equal share

A helper who joins for all the days does not get an equal part of the money. His share is the work he did: 1 minus what the others did in those days.

Summary — formulas & gotchas at a glance

A revision cheat-sheet for the formulas and gotchas above. Click any concept name to jump back to its full explanation.

Formulas (4)

  • Workers together: add the one-day rates

    Working together

    Rate=1nT=aba+bT=11a+1b+1c\text{Rate} = \frac{1}{n} \qquad T = \frac{ab}{a + b} \qquad T = \frac{1}{\frac{1}{a} + \frac{1}{b} + \frac{1}{c}}
  • Part of the job done in a given time

    Work done and work left

    W=tnLeft=1−WWhole time=dfW = \frac{t}{n} \qquad \text{Left} = 1 - W \qquad \text{Whole time} = \frac{d}{f}
  • One worker's time from the team's time

    Finding one worker

    x=abb−aA+B+C=(A+B)+(B+C)+(C+A)2x = \frac{ab}{b - a} \qquad A + B + C = \frac{(A + B) + (B + C) + (C + A)}{2}
  • Sharing the pay by work done

    Pay shared by work

    Share=work donewhole job×total pay\text{Share} = \frac{\text{work done}}{\text{whole job}} \times \text{total pay}

Watch out for (8)

Test yourself on Time and Work

20 past SSC CGL questions from this chapter, timed at 12 minutes and marked the way the exam marks it. You see your score and every answer the moment you finish. Free to start.